Question

好的，首先，我想说我是Java Development的新手...... 考虑到这一点，我现在试图使tryWord的值包含空格而不是破折号，如果是s中的空格。谁能帮我？

    String tryWord = "";
    for (int i = 0; i < s.length(); i++) {
        tryWord += "-";
    }
    System.out.println(s + tryWord);

Value for s
------------
private static String randomOutput() {
    String array[] = new String[10];
    array[0] = "Hamlet";
    array[1] = "Mysts of Avalon";
    array[2] = "The Iliad";
    array[3] = "Tales from Edger Allan Poe";
    array[4] = "The Children of Hurin";
    array[5] = "The Red Badge of Courage";
    array[6] = "Of Mice and Men";
    array[7] =  "Utopia"; 
    array[8] =  "Chariots of the Gods";
    array[9] =  "a Brief History of Time";

    ArrayList<String> list = new ArrayList<String>(Arrays.asList(array));
    Collections.shuffle(list);
    String s = list.get(0);
    return s;
}

Answer 1

您可以在java中使用replace或replaceAll，它将解决问题

tryWord = s.replaceAll("\\s", "-");

Answer 2

使用此：

 tryWord.replace(oldChar, newChar);

Answer 3

   tryWord += s.charAt(i) == ' ' ? " " : "-";

这称为三元表达式... ? ... : ...，一种带有字符的if是空格，然后是其他空格。

Answer 4

试试这个：

if (s.charAt(i) == ' ') {
   tryWord += ' ';
} else {
   tryWord += '-';
}

在空格的情况下包括空格而不是破折号

4 个答案: