我有一个不同大小的图片库。每个图像按顺序显示在ImageView
内(通过OnTouchListener
)。我需要知道我正在向ImageView
显示亲属的图片框架的位置,但是通过我已经完成的测试,我只获得了ImageView
的坐标。有什么想法吗?
我需要(x1,y1)和(x2,y2)的值。
提前致谢。
这是我的班级:
public class PuzzleView extends ImageView {
protected Paint currentPaint;
protected boolean drawRect = false;
protected float left;
protected float top;
protected float right;
protected float bottom;
protected float pixelX;
protected float pixelY;
protected int nChunksX = 5;
protected int nChunksY = 5;
protected int currentWidth = 0;
protected int currentHeight = 0;
public PuzzleView(Context context, AttributeSet attrs) {
super(context, attrs);
currentPaint = new Paint();
currentPaint.setDither(true);
currentPaint.setColor(0xFF00CC00);
currentPaint.setStyle(Paint.Style.STROKE);
currentPaint.setStrokeJoin(Paint.Join.ROUND);
currentPaint.setStrokeCap(Paint.Cap.ROUND);
currentPaint.setStrokeWidth(2);
}
@Override
protected void onDraw(Canvas canvas) {
super.onDraw(canvas);
float chunkWidth = currentWidth / nChunksX;
float chunkHeight = currentHeight / nChunksY;
float posX = ((int)(pixelX / chunkWidth)) * chunkWidth;
float posY = ((int)(pixelY / chunkHeight)) * chunkHeight;
canvas.drawRect(posX, posY, posX + chunkWidth, posY + chunkHeight, currentPaint);
Rect rect = this.getDrawable().getBounds();
canvas.drawRect(rect, currentPaint);
}
@Override
protected void onMeasure(int widthMeasureSpec, int heightMeasureSpec) {
super.onMeasure(widthMeasureSpec, heightMeasureSpec);
// Get image matrix values and place them in an array
float[] f = new float[9];
getImageMatrix().getValues(f);
// Extract the scale values using the constants (if aspect ratio maintained, scaleX == scaleY)
final float scaleX = f[Matrix.MSCALE_X];
final float scaleY = f[Matrix.MSCALE_Y];
// Get the drawable (could also get the bitmap behind the drawable and getWidth/getHeight)
final Drawable d = getDrawable();
final int origW = d.getIntrinsicWidth();
final int origH = d.getIntrinsicHeight();
// Calculate the actual dimensions
final int actW = Math.round(origW * scaleX);
final int actH = Math.round(origH * scaleY);
currentWidth = actW;
currentHeight = actH;
}
public boolean isDrawRect() {
return drawRect;
}
public void setDrawRect(boolean drawRect) {
this.drawRect = drawRect;
}
public float getLeftRect() {
return left;
}
public void setLeftRect(float left) {
this.left = left;
}
public float getTopRect() {
return top;
}
public void setTopRect(float top) {
this.top = top;
}
public float getRightRect() {
return right;
}
public void setRightRect(float right) {
this.right = right;
}
public float getBottomRect() {
return bottom;
}
public void setBottomRect(float bottom) {
this.bottom = bottom;
}
public float getPixelX() {
return pixelX;
}
public void setPixelX(float pixelX) {
this.pixelX = pixelX;
}
public float getPixelY() {
return pixelY;
}
public void setPixelY(float pixelY) {
this.pixelY = pixelY;
}
public int getChunksX() {
return nChunksX;
}
public void setChunksX(int nChunksX) {
this.nChunksX = nChunksX;
}
public int getChunksY() {
return nChunksY;
}
public void setChunksY(int nChunksY) {
this.nChunksY = nChunksY;
}
}
目前,源图像是在XML文件中定义的:
<com.jocajica.shakepic.PuzzleView
android:id="@+id/imageViewSelected"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:layout_centerHorizontal="true"
android:layout_centerVertical="true"
android:contentDescription="@string/image_selected"
android:src="@android:drawable/progress_indeterminate_horizontal" />
我需要在图像上画一个网格。
答案 0 :(得分:11)
根据Jacob Nordfalk的链接,我能够生成一种静态方法,允许您从ImageView获取图像位置和尺寸。
/**
* Returns the bitmap position inside an imageView.
* @param imageView source ImageView
* @return 0: left, 1: top, 2: width, 3: height
*/
public static int[] getBitmapPositionInsideImageView(ImageView imageView) {
int[] ret = new int[4];
if (imageView == null || imageView.getDrawable() == null)
return ret;
// Get image dimensions
// Get image matrix values and place them in an array
float[] f = new float[9];
imageView.getImageMatrix().getValues(f);
// Extract the scale values using the constants (if aspect ratio maintained, scaleX == scaleY)
final float scaleX = f[Matrix.MSCALE_X];
final float scaleY = f[Matrix.MSCALE_Y];
// Get the drawable (could also get the bitmap behind the drawable and getWidth/getHeight)
final Drawable d = imageView.getDrawable();
final int origW = d.getIntrinsicWidth();
final int origH = d.getIntrinsicHeight();
// Calculate the actual dimensions
final int actW = Math.round(origW * scaleX);
final int actH = Math.round(origH * scaleY);
ret[2] = actW;
ret[3] = actH;
// Get image position
// We assume that the image is centered into ImageView
int imgViewW = imageView.getWidth();
int imgViewH = imageView.getHeight();
int top = (int) (imgViewH - actH)/2;
int left = (int) (imgViewW - actW)/2;
ret[0] = left;
ret[1] = top;
return ret;
}
答案 1 :(得分:1)
你应该使用getImageMatrix():
float[] imageMatrix = new float[9];
getImageMatrix().getValues(imageMatrix);
scale = imageMatrix[Matrix.MSCALE_X];
transX = imageMatrix[Matrix.MTRANS_X];
另见
Trying to get the display size of an image in an ImageView
答案 2 :(得分:0)
覆盖onLayout方法
//inside puzzleView
float[] matrix = new float[9];
@Override
protected void onLayout(boolean changed, int left, int top, int right, int bottom) {
super.onLayout(changed, left, top, right, bottom);
matrix = getMatrix();
}
public void getMatrix(){
return matrix;
}
private float[] getMatrix() {
final float[] matrix = new float[9];
getImageMatrix().getValues(matrix);
return matrix;
}
并使用它来获取值
// Extract the scale and translation values from the matrix.
float scaleX = matrix[Matrix.MSCALE_X];
float scaleY = matrix[Matrix.MSCALE_Y];
float transX = matrix[Matrix.MTRANS_X];
float transY = matrix[Matrix.MTRANS_Y];
我希望这有助于你