我正在测试将Array List显示为JavaFX手风琴:
public class Navigation {
// Object for storing conenctions
public static List<dataObj> list = new ArrayList<>();
private ObservableList<dataObj> data;
public class dataObj {
private String conenctionname;
public dataObj(String conenctionname) {
this.conenctionname = conenctionname;
}
public String getConenctionname() {
return conenctionname;
}
public void setConenctionname(String conenctionname) {
this.conenctionname = conenctionname;
}
}
public void initNavigation(Stage primaryStage, Group root, Scene scene) {
VBox stackedTitledPanes = createStackedTitledPanes();
ScrollPane scroll = makeScrollable(stackedTitledPanes);
scroll.getStyleClass().add("stacked-titled-panes-scroll-pane");
scroll.setPrefSize(395, 580);
scroll.setLayoutX(5);
scroll.setLayoutY(32);
root.getChildren().add(scroll);
}
private ScrollPane makeScrollable(final VBox node) {
final ScrollPane scroll = new ScrollPane();
scroll.setContent(node);
scroll.viewportBoundsProperty().addListener(new ChangeListener<Bounds>() {
@Override
public void changed(ObservableValue<? extends Bounds> ov, Bounds oldBounds, Bounds bounds) {
node.setPrefWidth(bounds.getWidth());
}
});
return scroll;
}
/////////////////////////////////////////////////////////////////////////////////////
// Generate accordition with Connections, Tables and Description
private VBox createStackedTitledPanes() {
VBox stackedTitledPanes = new VBox();
stackedTitledPanes.getChildren().setAll(
createConnectionsList("Connections"));
((TitledPane) stackedTitledPanes.getChildren().get(0)).setExpanded(true);
stackedTitledPanes.getStyleClass().add("stacked-titled-panes");
return stackedTitledPanes;
}
//////////////////////////////////////////////////////////////////////////////
// Generate list with Connections
public TitledPane createConnectionsList(String title) {
initObject();
data = FXCollections.observableArrayList(list);
ListView<dataObj> lv = new ListView<>(data);
lv.setCellFactory(new Callback<ListView<dataObj>, ListCell<dataObj>>() {
@Override
public ListCell<dataObj> call(ListView<dataObj> p) {
return new ConnectionsCellFactory();
}
});
AnchorPane content = new AnchorPane();
content.getChildren().add(lv);
// add to TitelPane
TitledPane pane = new TitledPane(title, content);
return pane;
}
static class ConnectionsCellFactory extends ListCell<dataObj> {
@Override
public void updateItem(dataObj item, boolean empty) {
super.updateItem(item, empty);
if (item != null) {
for (int i = 0; i < list.size(); i++) {
setText(list.get(i).getConenctionname());
}
}
}
}
// Insert Some test data
public void initObject() {
dataObj test1 = new dataObj("test data 1");
dataObj test2 = new dataObj("test data 2");
list.add(test1);
list.add(test2);
}
}
但由于某种原因,我无法从数组列表中获取正确的对象列表并显示它们。我得到了这个结果:
正确的结果应该是test data 1
和test data 2
。我怎么解决这个问题?
答案 0 :(得分:1)
问题出在ConnectionsCellFactory
,为List中的每个项调用方法updateItem
。因此,在您的代码中,您为列表中的每个项目设置文本的每个单元格
你应该尝试:
static class ConnectionsCellFactory extends ListCell<dataObj> {
@Override
public void updateItem(dataObj item, boolean empty) {
super.updateItem(item, empty);
if (item != null) {
setText(item.getConenctionname());
}
}
}