我试图让我的图像(鸟)在屏幕上上下移动,但我无法弄清楚如何做到这里是我试图确定它的方式,但我试图找出它,如果有人可以帮助那会很棒!
import pygame
import os
screen = pygame.display.set_mode((640, 400))
running = 1
while running:
event = pygame.event.poll()
if event.type == pygame.QUIT:
running = 0
screen.fill([255, 255, 255])
clock = pygame.time.Clock()
clock.tick(0.5)
pygame.display.flip()
bird = pygame.image.load(os.path.join('C:\Python27', 'player.png'))
screen.blit( bird, ( 0, 0 ) )
pygame.display.update()
class game(object):
def move(self, x, y):
self.player.center[0] += x
self.player.center[1] += y
if event.key == K_UP:
player.move(0,5)
if event.key == K_DOWN:
player.move(0,-5)
game()
我试图让它向下按下向下按钮然后按向上键按
答案 0 :(得分:10)
如ecline6所述,此时鸟类是您最不担心的。
考虑阅读this book ..
现在,首先让我们清理你的代码......
import pygame
import os
# let's address the class a little later..
pygame.init()
screen = pygame.display.set_mode((640, 400))
# you only need to call the following once,so pull them out of the while loop.
bird = pygame.image.load(os.path.join('C:\Python27', 'player.png'))
clock = pygame.time.Clock()
running = True
while running:
event = pygame.event.poll()
if event.type == pygame.QUIT:
running = False
screen.fill((255, 255, 255)) # fill the screen
screen.blit(bird, (0, 0)) # then blit the bird
pygame.display.update() # Just do one thing, update/flip.
clock.tick(40) # This call will regulate your FPS (to be 40 or less)
现在你的“鸟”不动的原因是:
当您对图像进行blit时,即:screen.blit(bird, (0, 0))
,
(0,0)
是常量,因此不会移动。
这是最终代码,包含您想要的输出(试一试)并阅读注释:
import pygame
import os
# it is better to have an extra variable, than an extremely long line.
img_path = os.path.join('C:\Python27', 'player.png')
class Bird(object): # represents the bird, not the game
def __init__(self):
""" The constructor of the class """
self.image = pygame.image.load(img_path)
# the bird's position
self.x = 0
self.y = 0
def handle_keys(self):
""" Handles Keys """
key = pygame.key.get_pressed()
dist = 1 # distance moved in 1 frame, try changing it to 5
if key[pygame.K_DOWN]: # down key
self.y += dist # move down
elif key[pygame.K_UP]: # up key
self.y -= dist # move up
if key[pygame.K_RIGHT]: # right key
self.x += dist # move right
elif key[pygame.K_LEFT]: # left key
self.x -= dist # move left
def draw(self, surface):
""" Draw on surface """
# blit yourself at your current position
surface.blit(self.image, (self.x, self.y))
pygame.init()
screen = pygame.display.set_mode((640, 400))
bird = Bird() # create an instance
clock = pygame.time.Clock()
running = True
while running:
# handle every event since the last frame.
for event in pygame.event.get():
if event.type == pygame.QUIT:
pygame.quit() # quit the screen
running = False
bird.handle_keys() # handle the keys
screen.fill((255,255,255)) # fill the screen with white
bird.draw(screen) # draw the bird to the screen
pygame.display.update() # update the screen
clock.tick(40)
答案 1 :(得分:0)
键盘事件(参见 pygame.event 模块)仅在键的状态改变时发生一次。 KEYDOWN
事件在每次按下键时发生一次。 KEYUP
每次释放键时出现一次。将键盘事件用于单个操作或逐步移动。
如果要实现连续运动,则必须使用pygame.key.get_pressed()
。 pygame.key.get_pressed()
返回一个包含每个键状态的列表。如果某个键被按下,则该键的状态为 True
,否则为 False
。使用 pygame.key.get_pressed()
评估按钮的当前状态并获得连续移动。
另见Key and Keyboard event和How can I make a sprite move when key is held down。
最小示例:
import pygame
import os
class Bird(object):
def __init__(self):
self.image = pygame.image.load(os.path.join('C:\Python27', 'player.png'))
self.center = [100, 200]
def move(self, x, y):
self.center[0] += x
self.center[1] += y
def draw(self, surf):
surf.blit(self.image, self.center)
class game(object):
def __init__(self):
self.screen = pygame.display.set_mode((640, 400))
self.clock = pygame.time.Clock()
self.player = Bird()
def run(self):
running = 1
while running:
self.clock.tick(60)
event = pygame.event.poll()
if event.type == pygame.QUIT:
running = 0
keys = pygame.key.get_pressed()
move_x = keys[pygame.K_RIGHT] - keys[pygame.K_LEFT]
move_y = keys[pygame.K_DOWN] - keys[pygame.K_UP]
self.player.move(move_x * 5, move_y * 5)
self.screen.fill([255, 255, 255])
self.player.draw(self.screen)
pygame.display.update()
g = game()
g.run()