Question

请帮我解决使用Oracle数据库的以下SQL问题

提示：按升序PK序列列出仓库表的所有列。 •仅列出地址以RD或ST结尾的行

SELECT *
FROM warehouse 
WHERE address ='% rd' 
OR WHERE address ='% st',
ORDER BY whid ASC;

错误消息：

OR WHERE address ='％st'，*

第4行出错：ORA-00936：表达式缺失

Answer 1

您不需要第二个WHERE，也应该删除逗号。此外，您可能希望在地址之前有LIKE，并且您可能不希望拥有空格。

我认为你的意思是：

SELECT *
FROM warehouse 
WHERE address LIKE '%rd' 
OR address LIKE '%st'
ORDER BY whid ASC;

或者，你可能很聪明：

-- You don't say this explicitly, but I think it a good idea to make sure that 
-- you are searching for rd and st in the right tense. That is why I have 'lower'
SELECT *
FROM warehouse 
WHERE lower(substr(address,-2,2)) in ('rd', 'st')
ORDER BY whid ASC;

Answer 2

删除第二个WHERE语句，并将等效语句更改为LIKE。

SELECT *
FROM warehouse 
WHERE address LIKE '% rd' 
OR address LIKE '% st'
ORDER BY whid ASC;

如果您在那里有等效语句，则只会匹配完全等于% rd或% st的字符串。

Answer 3

摆脱第二个WHERE，使用LIKE代替=并尝试删除%字符后的空格。

SELECT *
FROM warehouse 
WHERE address LIKE '%rd' 
OR address LIKE '%st'
ORDER BY whid ASC;

Answer 4

使用LIKE关键字：

SELECT * FROM warehouse WHERE address LIKE '%RD' OR address LIKE '%ST' ORDER BY whid ASC;

SQL Oracle错误 - 家庭作业任务

4 个答案: