Question

我不是要回复结果集，我不知道我在这里做错了什么。 MySQL 5.5

delimiter $$

CREATE FUNCTION CheckAccount(
    i_username varchar(50)
) RETURNS integer

BEGIN

    DECLARE v_validUserId int;
    DECLARE v_validMembership int;
    DECLARE o_Status integer;

    SELECT vvalidUserId = u.UserId
    FROM Users u
    WHERE u.Username = i_username;

    IF( v_validUserId IS NULL ) THEN
        SET o_Status = 2; -- Invalid username
    ELSE
        SET o_Status = 1; -- Good
    END IF;


    IF(o_Status != 2 ) THEN
            SELECT v_validMembership = 1
            FROM Users u
            JOIN UserMemberships um on um.UserId = u.userId
            JOIN Memberships m on m.MembershipId = um.MembershipId
            WHERE um.MembershipExpireDateTime > CURDATE()
            AND u.UserId = v_validUserId;

            IF( v_validMembership IS NULL ) THEN 
                SET o_Status = 3; -- Invalid membership
            END IF;
    END IF;

    RETURN o_status;

END $$
DELIMITER ;

任何帮助将不胜感激！

Answer 1

我不确定您是否可以通过这种方式分配变量，请尝试使用INTO语句进行选择。例如：

SELECT 
    u.UserId INTO vvalidUserId 
FROM 
    Users u
WHERE 
    u.Username = i_username;

MySQL函数 - 错误代码：1415不允许从函数返回结果集

1 个答案: