Question

我一直在尝试实现一个从wordnet的在线数据库读取的bash脚本，并且一直想知道是否有办法用一个命令删除各种文本文件。

示例FileDump：

**** Noun ****
(n)hello, hullo, hi, howdy, how-do-you-do (an expression of greeting) "every morning they exchanged polite hellos"
**** Verb ****
(v)run (move fast by using one's feet, with one foot off the ground at any given time) "Don't run--you'll be out of breath"; "The children ran to the store"
**** Adjective ****
(adj)running ((of fluids) moving or issuing in a stream) "as mountain stream with freely running water"; "hovels without running water"

我只需要删除描述语法方面的行，例如

**** Noun ****
**** Verb ****
**** Adjective ****

所以我有一个只有单词定义的干净文件：

(n)hello, hullo, hi, howdy, how-do-you-do (an expression of greeting) "every morning they exchanged polite hellos"
(v)run (move fast by using one's feet, with one foot off the ground at any given time) "Don't run--you'll be out of breath"; "The children ran to the store"
(adj)running ((of fluids) moving or issuing in a stream) "as mountain stream with freely running water"; "hovels without running water"

语法术语周围的*符号让我在sed中绊倒。

Answer 1

如果您想根据这些行的内容从文件中选择整行，grep可能是最合适的工具。但是，某些字符（例如您的星星）对grep具有特殊含义，因此需要使用反斜杠“转义”。这将只打印以四颗星和一个空格开头的行：

grep "^\*\*\*\* " textfile

但是，您希望保留不匹配的行，因此您需要-v的{{1}}选项才能执行此操作：打印行不匹配模式。

grep

那可以给你你想要的东西。

Answer 2

sed '/^\*\{4\} .* \*\{4\}$/d'

或者有点宽松

sed '/^*\{4\}/d'

Answer 3

 sed 's/^*.*//g' test | grep .

Answer 4

# awk '!/^\*\*+/' file
(n)hello, hullo, hi, howdy, how-do-you-do (an expression of greeting) "every morning they exchanged polite hellos"
(v)run (move fast by using one's feet, with one foot off the ground at any given time) "Don't run--you'll be out of breath"; "The children ran to the store"
(adj)running ((of fluids) moving or issuing in a stream) "as mountain stream with freely running water"; "hovels without running water"

删除文本文件中的各种行

4 个答案: