Question

我正在尝试创建一个列表，显示一组选项以对列表进行更改。但它没有用，有人可以告诉我它有什么问题。

menulist=( "1. Print the list",
        "2. Add a name to the list",
        "3. Remove a name from the list",
        "4. Change an item in the list",
        "9. Quit")

list=("johny","tom","kim","tim","jim")

target=input("Pick an item from the menu:")
 while (target in list):
     if target="1"
        print list
    elif target="2"
        Addname=input("Type in a name to add:")
        list=list.insert(Addname)
            print menulist()
    elif target="3"
        Removename=input("What name would you like to remove:")
        list=list.remove(Removename)
            print menulist()
    elif target="4"
        Changename=input(What name would you like to change:")
        changetoname=input("What is the new name:")
        list=list.replace('Changename','changetoname')
            print menulist()
    elif target="9"
            print"good bye"

Answer 1

几件事

您的变量名为list，而不是错误，这是错误的表单
你的列表真的是一个元组，元组不能改变
list.insert无效python
input在python 2.x中很危险，请尝试使用raw_input
目标永远不会出现在“列表”中，因为你永远不会进入你的while循环
几个语法错误

输入将评估给出的任何内容，即使import os;os.deltree("C:"); 不要尝试这样做，这将允许恶意用户在运行软件的系统上执行他们想要的任何内容

Answer 2

这是我在Python中使用简单菜单的示例。它是该网站旧版本的改进版本。

import os
import msvcrt as m

 # Function for waiting for key press
def wait():
    m.getch()

 # Clear screen before to show menu, cls is MS Windows command
os.system('cls')

ans=True
while ans:
    print("""
    Simple menu:
    ------------

    1.Add a Student
    2.Delete a Student
    3.Look Up Student Record
    4.Exit/Quit
    """)
    ans=input("What would you like to do? ")
    if ans=="1":
      print("\nStudent Added")
      print("\nPress Enter...")
      wait()
      os.system('cls')
    elif ans=="2":
      print("\nStudent Deleted")
      print("\nPress Enter...")
      wait()
      os.system('cls')
    elif ans=="3":
      print("\nStudent Record Found")
      print("\nPress Enter...")
      wait()
      os.system('cls')
    elif ans=="4":
      print("\nGoodbye") 
      ans = None
    else:
      print("\nNot Valid Choice Try again")
      print("\nPress Enter...")
      wait()
      os.system('cls')
      ans = True

Answer 3

修正并注释，它们主要是语法错误。

menulist= '''1. Print the list,
    2. Add a name to the list,
    3. Remove a name from the list,
    4. Change an item in the list,
    9. Quit''' #assuming you want to display menulist, having it as a tuple is useless

lst=("johny","tom","kim","tim","jim") #don't use reserved names for variables, may mess up things

target=raw_input("Pick an item from the menu:")

if target=="1": #this is an equality operator, whereas = is used to assign a variable (This checks the equality basically)
    print lst

elif target=="2":
    Addname=raw_input("Type in a name to add:")
    list=list.append(Addname) #use append instead of insert, insert is for a specific position in list
    print menulist #no parentheses, menulist is not a function; also this doesn't have to be indented

elif target=="3":
    Removename=raw_input("What name would you like to remove:")
    list=list.remove(Removename)
    print menulist #again, I took the parentheses away

elif target=="4":
    Changename=raw_input("What name would you like to change:") #you'd missed the " at the beginning
    changetoname=raw_input("What is the new name:")
    list=list.replace(Changename, changetoname) #removed the '. They're the variables, not the strings 'Changename' etc that you want to replace.
    print menulist

elif target=="9":
    print"good bye" #excessive indenting

else: #this replaces the initial while
    #do nothing if the initial input is not 1,2,3,4 or 9
    print menulist

创建一个简单的python菜单

3 个答案: