我有一张包含40列的表格。
我希望编写一个查询,它将返回每列中空值/空值的数量。
实施例,
如果有A,B,C和D列。
我想要的输出是:
A|B|C|D
3|5|4|9
其中3是记录数: 其中A为null或A ='' 等等...
任何帮助将不胜感激。 我正在使用MS SQL 2008 R2
答案 0 :(得分:6)
试试这个 -
DECLARE @temp TABLE
(
A VARCHAR(50)
, B VARCHAR(50)
, C VARCHAR(50)
, D VARCHAR(50)
)
INSERT INTO @temp (A, B, C, D)
VALUES
('', 'dr', '1', NULL),
('d', NULL, '45', 'h')
SELECT
A = COUNT(CASE WHEN ISNULL(A, '') = '' THEN 1 END)
, B = COUNT(CASE WHEN ISNULL(B, '') = '' THEN 1 END)
, C = COUNT(CASE WHEN ISNULL(C, '') = '' THEN 1 END)
, D = COUNT(CASE WHEN ISNULL(D, '') = '' THEN 1 END)
FROM @temp
<强>更新强>
在这种情况下,请尝试动态sql -
DECLARE @TableName SYSNAME
SELECT @TableName = 'dbo.test1'
DECLARE @SQL NVARCHAR(MAX)
SELECT @SQL = 'SELECT' + CHAR(13) + STUFF((
SELECT CHAR(13) + ', ' + c.name + ' = COUNT(CASE WHEN ISNULL(CAST(' + c.name + ' AS NVARCHAR(MAX)), '''') = '''' THEN 1 END)'
FROM (
SELECT o.[object_id]
FROM sys.objects o
JOIN sys.schemas s ON o.[schema_id] = s.[schema_id]
WHERE o.[type] = 'U'
AND s.name + '.' + o.name = @TableName
) o
JOIN sys.columns c ON o.[object_id] = c.[object_id]
FOR XML PATH(''), TYPE).value('.', 'NVARCHAR(MAX)'), 1, 2, ' ') + CHAR(13) + 'FROM ' + @TableName
PRINT @SQL
EXEC sys.sp_executesql @SQL
在输出中你可以得到类似的东西:
SELECT
WorkOutID = COUNT(CASE WHEN ISNULL(CAST(WorkOutID AS NVARCHAR(MAX)), '') = '' THEN 1 END)
, TimeSheetDate = COUNT(CASE WHEN ISNULL(CAST(TimeSheetDate AS NVARCHAR(MAX)), '') = '' THEN 1 END)
, DateOut = COUNT(CASE WHEN ISNULL(CAST(DateOut AS NVARCHAR(MAX)), '') = '' THEN 1 END)
, EmployeeID = COUNT(CASE WHEN ISNULL(CAST(EmployeeID AS NVARCHAR(MAX)), '') = '' THEN 1 END)
, IsMainWorkPlace = COUNT(CASE WHEN ISNULL(CAST(IsMainWorkPlace AS NVARCHAR(MAX)), '') = '' THEN 1 END)
, DepartmentUID = COUNT(CASE WHEN ISNULL(CAST(DepartmentUID AS NVARCHAR(MAX)), '') = '' THEN 1 END)
, WorkPlaceUID = COUNT(CASE WHEN ISNULL(CAST(WorkPlaceUID AS NVARCHAR(MAX)), '') = '' THEN 1 END)
, WorkShiftCD = COUNT(CASE WHEN ISNULL(CAST(WorkShiftCD AS NVARCHAR(MAX)), '') = '' THEN 1 END)
, TeamUID = COUNT(CASE WHEN ISNULL(CAST(TeamUID AS NVARCHAR(MAX)), '') = '' THEN 1 END)
, WorkHours = COUNT(CASE WHEN ISNULL(CAST(WorkHours AS NVARCHAR(MAX)), '') = '' THEN 1 END)
, AbsenceCode = COUNT(CASE WHEN ISNULL(CAST(AbsenceCode AS NVARCHAR(MAX)), '') = '' THEN 1 END)
, PaymentType = COUNT(CASE WHEN ISNULL(CAST(PaymentType AS NVARCHAR(MAX)), '') = '' THEN 1 END)
FROM dbo.test1
答案 1 :(得分:1)
试试这个
DECLARE @cols1 NVARCHAR(MAX);
DECLARE @sql NVARCHAR(MAX);
SELECT @cols1 = STUFF((
SELECT ', COUNT(CASE WHEN ISNULL(CONVERT(NVARCHAR(MAX), [' + t1.NAME + ']), '''') = '''' THEN 1 END) AS ' + t1.name
FROM sys.columns AS t1
WHERE t1.object_id = OBJECT_ID('myTable')
--ORDER BY ', COUNT([' + t1.name + ']) AS ' + t1.name
FOR XML PATH('')
), 1, 2, '');
SET @sql = '
SELECT ' + @cols1 + '
FROM myTable
'
EXEC(@sql)