我正在使用同义词/别名管理器数据库,用户可以在其中存储他们认为正确的关联。假设用户键入“rabbit”并且未找到任何同义词或别名。然后用户决定将“兔子”与“兔子”相关联并将其存储到数据库中。任何其他用户在“兔子”中输入“兔子”的结果时,都会出现。但是,我正在尝试实现一个轮询系统,询问用户是否认为关联是正确的。如果他们认为“兔子”适合“兔子”,那么他们投赞成票,否则不投票。这是我被困的地方。加载轮询并按提交后,所有内容都会消失,并且不会将任何内容发送到数据库。代码如下:
$query = "SELECT * from searchtestdb where engname in ( SELECT synonyms.synonym FROM words LEFT JOIN synonyms ON synonyms.word_id = words.word_id WHERE word LIKE '%$searchBox%') "; // Query for animals in db
$query = mysql_query($query);
if(mysql_num_rows($query) == 0)
{
echo "<h2>Aliases: </h2>";
echo "Sorry, but we can not find an alias to match your query.";
echo "<br> ";
}
else
{
echo "<h2> Results using Alias: </h2>";
while($result = mysql_fetch_array($query))
{
$query2 = "SELECT * from searchtestdb where engname LIKE '%".$result['engname']."%';";
$result2 = mysql_query($query2);
while($row = mysql_fetch_array($result2))
{
print "<h4>Latin Name: </h4> ";
echo $row["latname"];
echo "<br> ";
print"<h4>English Name:</h4> ";
echo $row["engname"];
echo "<br>";
print "<h4> Species: </h4> ";
echo $row["spectype"];
print "<h4>Characteristics: </h4> ";
echo $row["charc1"];
echo "<br>";
echo $row["charc2"];
echo "<br>";
echo $row["charc3"];
echo "<br>";
}
}
$self = $_SERVER['PHP_SELF'];
print "<form method='post' action='$self' >\n";
print "<h4>Alias Association Correct? : </h4>";
print "<p>" .
"<input type='radio' name='vote' id='vote' value='1' /> \n" .
"Yes" .
"<input type='radio' name='vote' id='vote' value='2' /> \n" .
"No" .
"</p> \n" .
"<p>" .
"<input type='submit'name='submitVote' value='Submit' />" .
"\n </p> \n" .
"</form> \n" .
$vote=htmlentities($_POST['vote']);
echo $vote;
mysql_connect(----------------------) or die(mysql_error());
mysql_select_db("-----------") or die(mysql_error());
if($vote == 1)
{
mysql_query("INSERT INTO items(yes, uNo, word_id) VALUES ('0', '0', bunny');");
mysql_query("UPDATE items SET yes=yes+1 WHERE word_id='bunny';");
echo 'Thanks for voting Yes!';
}
if($vote == 2)
{ mysql_query("INSERT INTO items(word_id) VALUES ('".$result['engname']."'') ");
mysql_query("UPDATE items SET uNo=Uno+1 WHERE word_id='".$result['engname']."'");
echo "changos";
}
}
答案 0 :(得分:0)
简而言之,我犯了一个小错误:
$self = $_SERVER['PHP_SELF'];
应该是
$self = $_SERVER['POST'];
非常感谢。