Question

编译以下源代码时遇到了麻烦 [链接器错误]对'dish :: dish（）'的未定义引用 [链接器错误]未定义引用'dish ::〜dish（）' [链接器错误]未定义引用'dish :: ShowResult（）'有人可以帮助我吗？

HEADER FILE（dish.h）：

#ifndef DISH_H
#define DISH_H

class dish {
  public:
    dish();
    dish(std::string name, std::string variety, float caloric, float price);
    ~dish();
    static int GetN();
    void SetN(int N);
    static int IncrementN();
    std::string GetName() const;
    void SetName(std::string name);
    std::string GetVariety() const;
    void SetVariety(std::string variety);
    float GetCaloric() const;
    void SetCaloric(float caloric);
    float GetPrice() const;
    void SetPrice(float price);
    void Enter();
    void ShowResult();

  private:
    std::string name;
    std::string variety;
    float caloric;
    float price;
    static int N;

};

int dish::N;

#endif

和dish.cpp：

#include <iostream>
#include  <cstring>
#include "dish.h"

dish::dish()
{ 
    dish::Enter();
}

dish::dish(std::string name, std::string variety, float caloric, float price)
{
    this->name = name;
    this->variety = variety;
    this->caloric = caloric;
    this->price = price;
}

dish::~dish() 
{             
}

static int dish::GetN()
{ 
    return N; 
}

void dish::SetN(int N)
{ 
     this->N = N; 
}

static int dish::IncrementN() 
{ 
    N++; 
}

std::string dish::GetName() const 
{ 
    return name; 
}

void dish::SetName(std::string name) 
{ 
    dish::name = name; 

}

std::string dish::GetVariety() const 
{ 
    return variety;
}

void dish::SetVariety(std::string variety) 
{ 
    dish::variety = variety; 
}

float dish::GetCaloric() const 
{ 
    return caloric; 
}

void dish::SetCaloric(float caloric) 
{ 
    this->caloric = caloric; 
}

float dish::GetPrice() const 
{ 
    return price; 
}

void dish::SetPrice(float price) 
{ 
    this->price = price; 
}

void dish::Enter()
{
    std::cout << "\n \\*_________________________________*\\\n"; 
    std::cout << "\n   ENTER THE NAME OF DISH: ";
    getline(std::cin, name);
    std::cout << "   ENTER THE VARIETY: ";
    getline(std::cin, variety);
    std::cout << "   ENTER THE CALORIC CONTENT: ";
    (std::cin >> caloric).get();
    std::cout << "   ENTER THE PRICE: ";
    (std::cin >> price).get();
    std::cout << "\n \\*_________________________________*\\\n"; 
    dish::IncrementN();
}   

void dish::ShowResult() 
{
    std::cout << "\n \\*________________________*\\\n"; 
    std::cout << "\n   THE NAME OF DISH: " << dish::GetName() << std::endl;
    std::cout << "   THE VARIETY: " << dish::GetVariety() << std::endl;
    std::cout << "   THE CALORIC CONTENT: " << dish::GetCaloric() << std::endl;
    std::cout << "   THE PRICE: " << dish::GetPrice() << std::endl;
    std::cout << "\n \\*________________________*\\\n";    
}

主要实施......

#include <cstring>
using namespace std; 
#include "dish.h"


int main() {
    dish a;
    a.ShowResult();
   return 0;
}

Answer 1

您应该将dish.cpp与您的主要可执行文件链接，即在您的项目中添加dish.cpp。

Answer 2

这是一个语法错误，会在dish.cpp上产生编译错误。链接错误只是其结果。

从dish.cpp中删除static个关键字。

请记住，唯一有趣的错误几乎总是第一个。

说明：为了执行类方法，只在头文件中写入static，而不是在.cpp中。

有关信息，但这显然不是您尝试做的事情：.cpp中的static可用于使函数在编译单元外部不可见，但实际上是从C继承的不推荐构造。应该更喜欢匿名命名空间。

链接器错误：C ++中对class ::'methods'的未定义引用

2 个答案: