我有一个代码可以给我这样的列表:
Name id number week number
Piata 4 6
Mali 2 20,5
Goerge 5 4
Gooki 3 24,64,6
Mali 5 45,9
Piata 6 1
Piata 12 2,7,8,27,16 etc..
使用以下代码:
import csv
from datetime import date
datedict = defaultdict(set)
with open('d:/info.csv', 'r') as csvfile:
filereader = csv.reader(csvfile, 'excel')
#passing the header
read_header = False
start_date=date(year=2009,month=1,day=1)
#print((seen_date - start_date).days)
tdic = {}
for row in filereader:
if not read_header:
read_header = True
continue
# reading the rest rows
name,id,firstseen = row[0],row[1],row[3]
try:
seen_date = datetime.datetime.strptime(firstseen, '%d/%m/%Y').date()
deltadays = (seen_date-start_date).days
deltaweeks = deltadays/7 + 1
key = name,id
currentvalue = tdic.get(key, set())
currentvalue.add(deltaweeks)
tdic[key] = currentvalue
except ValueError:
print('Date value error')
pass
现在我想将我的列表转换为一个列表,该列表为每个名称及其周数提供了一些ID,如下面的列表所示:
Name number of ids weeknumbers
Mali 2 20,5,45,9
Piata 3 1,6,2,7,8,27,16
Goerge 1 4
Gooki 1 24,64,6
任何人都可以帮我编写这部分的代码吗?
答案 0 :(得分:0)
鉴于:
tdict = {('Mali', 5): set([9, 45]), ('Gooki', 3): set([24, 64, 6]), ('Goerge', 5): set([4]), ('Mali', 2): set([20, 5]), ('Piata', 4): set([4]), ('Piata', 6): set([1]), ('Piata', 12): set([8, 16, 2, 27, 7])}
然后输出上面的结果:
names = {}
for ((name, id), more_weeks) in tdict.items():
(ids, weeks) = names.get(name, (0, set()))
ids = ids + 1
weeks = weeks.union(more_weeks)
names[name] = (ids, weeks)
for (name, (id, weeks)) in names.items():
print("%s, %s, %s" % (name, id, weeks)
答案 1 :(得分:0)
由于您的csv文件看起来有标题(您当前正在忽略),为什么不使用DictReader
而不是标准reader
类?如果你不提供字段名,DictReader
会假设第一行包含它们,这也可以避免你跳过循环中的第一行。
这似乎是使用defaultdict
模块中的Counter
和collections
的绝佳机会。
import csv
from datetime import date
from collections import defaultdict, Counter
datedict = defaultdict(set)
namecounter = Counter()
with open('d:/info.csv', 'r') as csvfile:
filereader = csv.DictReader(csvfile)
start_date=date(year=2009,month=1,day=1)
for row in filereader:
name,id,firstseen = row['name'], row['id'], row['firstseen']
try:
seen_date = datetime.datetime.strptime(firstseen, '%d/%m/%Y').date()
except ValueError:
print('Date value error')
pass
deltadays = (seen_date-start_date).days
deltaweeks = deltadays/7 + 1
datedict[name].add(deltaweeks)
namecounter.update([name]) # Without putting name into a list, update will index each character
这假定(name, id)
是唯一的。如果不是这种情况,那么您可以使用其他defaultdict
作为namecounter
。我还移动了try-except语句,因此它在您测试的内容中更明确。