我有以下代码
XmlDocument docu = new XmlDocument();
docu.Load(file);
XmlNodeList lst = docu.GetElementsByTagName("name");
foreach (XmlNode n in lst)
{
string text = n.InnerText;
var types = doc.Element("program").Element("program-function").Element("function").Descendants("type").Where(x => x.Value == text).Select(c => c.Value).ToArray();
}
我的xml如下
<program>
<program-function>
<function>
<name>add</name>
<return-type>double</return-type>
<params>
<type>double</type>
<type-value>a</type-value>
<type>double</type>
<type-value>b</type-value>
<type>string</type>
<type-value>c</type-value>
</params>
<body> return a + b + c; </body>
</function>
<function>
<name>test</name>
<return-type>int</return-type>
<params>
<type>double</type>
<type-value>a</type-value>
<type>double</type>
<type-value>b</type-value>
</params>
<body> return a + b; </body>
</function>
</program-function>
</program>
我需要为每个<type>
<name>
的数量
添加的结果应为3 = types.count() = 3
测试结果应为2 = types.count() = 2
任何建议?
编辑:如果我想检索types
内的每个值?即。 add
应包含a
,b
,c
和test
应包含a
,b
。希望将它存储在数组中以便于检索
答案 0 :(得分:1)
如何使用Linq to Xml
var xDoc = XDocument.Parse(xml);
var functions = xDoc.Descendants("function")
.Select(f => new
{
Name = f.Element("name").Value,
Types = f.Descendants("type").Select(t=>t.Value).ToList(),
//Types = f.Descendants("type").Count()
TypeValues = f.Descendants("type-value").Select(t=>t.Value).ToList()
})
.ToList();
答案 1 :(得分:0)
试试这个:
XDocument doc = XDocument.Load(your file);
var vals = doc.Element("program").Element("program-function").Elements("function");
var result = vals.Select(i =>
new { name = i.Element("name"),
count = i.Elements("type").Count() }