你好我试图在两个结果集中检索数据。然后我将结果集存储到String Array中,在这个过程之后我必须将我的String数组存储到另一个表中,如何这样告诉我..
try {
Class.forName("com.mysql.jdbc.Driver");
Connection con = (Connection) DriverManager.
getConnection("jdbc:mysql://localhost:3306/lportal", "root", "ubuntu123");
PreparedStatement stmt = (PreparedStatement) con.
prepareStatement("SELECT * FROM Testi_Testimonial where subject = ?");
stmt.setString(1, search);
stmt.execute();
rs = (ResultSet) stmt.getResultSet();
while (rs.next()) {
anArray[i] = rs.getString("subject");
System.out.println(anArray[i]);
i++;
count++;
}
PreparedStatement stmt1 = (PreparedStatement) con.
prepareStatement("SELECT * FROM Testi_Testimonial where subject != ?");
stmt1.setString(1, search);
stmt1.execute();
rs1 = (ResultSet) stmt1.getResultSet();
while (rs1.next()) {
anArray[i] = rs1.getString("subject");
System.out.println(anArray[i]);
i++;
count++;
}
} catch (Exception e) {
e.printStackTrace();
System.out.println("problem in connection");
}
请告诉我应该如何将我的数组存储到Temp
表?我的“临时”表格列subject
我要将myArray
存储到subject
列...请告诉我该怎么做。
答案 0 :(得分:3)
在rs:
中获取结果集后尝试此操作 PreparedStatement st = (PreparedStatement) con.prepareStatement("insert into temp values(?)");
i=0;
while(rs.next())
{
st.setString(1,anArray[i]);
st.executeUpdate();
i++;
}
答案 1 :(得分:1)
您只需迭代arrayList。你将主题列表分别作为。
public class TestArrayList {
public static void main(String[] args) {
/*create two arrayList*/
List<String> tempOneList = new ArrayList<String>();
try {
Class.forName("com.mysql.jdbc.Driver");
Connection con = DriverManager.getConnection("jdbc:mysql://localhost:3306/vijay", "root", "root");
Statement st = con.createStatement();
ResultSet res = st.executeQuery("SELECT * FROM subjecttable");
while (res.next()) {
tempOneList.add(res.getString("subject"));
}
ResultSet resOne = st.executeQuery("SELECT * FROM subjecttabletwo");
while (resOne.next()) {
tempOneList.add(resOne.getString("subject"));
}
System.out.println("temp/List>>--" + tempOneList.size());
for(int i=0;i<tempOneList.size();i++){
System.out.println(tempOneList.get(i));
}
} catch (Exception e) {
e.printStackTrace();
System.out.println("problem in connection");
}
}
}
答案 2 :(得分:0)
PreparedStatement ps =
(PreparedStatement) con.prepareStatement("insert into temp values(?)");
j=0;
while(rs.next())
{
ps.setString(1,anArray[j]);
ps.executeUpdate();
j++;
}