Question

如果我没错，ISIN号码的最后位置是一个验证位。根据前11位数确定其值的数学函数是什么？

Answer 1

http://en.wikipedia.org/wiki/International_Securities_Identification_Number

计算ISIN校验位的过程类似于CUSIP中使用的“Modulus 10 Double Add Double”技术。要计算校验位，首先通过将字母表中的序号位置加到9来将任何字母转换为数字，这样A = 10和M = 22.从最右边的数字开始，每隔一个数字乘以2。（对于CUSIP校验位，这两个步骤相反。）将得到的数字字符串（大于9的数字变为两个单独的数字）相加。从以0结尾的最小数字减去这个总和大于或等于它：这给出了校验位，也就是模10的和10的十进制补码。也就是说，得到的总和，包括检查 - 数字，是10的倍数。

他们也有good example。

Answer 2

基于其他人的例子，这里有一个C＃实现，它将验证ISIN和CUSIP（以及其他一些Luhn变体）。

用法：

foreach (var isin in ValidIsins)
{
    var calculatedChecksum = SecuritiesValidation.CalculateChecksum(isin.Substring(0, 11));
    var actualChecksum = (isin.Last() - '0');
    Assert.AreEqual(calculatedChecksum, actualChecksum);
}
foreach (var cusip in ValidCusips)
{
    var calculatedChecksum = SecuritiesValidation.CalculateChecksum(cusip.Substring(0, 8), true, true);
    var actualChecksum = (cusip.Last() - '0');
    Assert.AreEqual(calculatedChecksum, actualChecksum);
}

实现：

public static class SecuritiesValidation
{
    public static int CalculateChecksum(IEnumerable<char> codeWithoutChecksum, bool reverseLuhn = false, bool allowSymbols = false)
    {
        return reverseLuhn
            ? codeWithoutChecksum
                .Select((c, i) => c.OrdinalPosition(allowSymbols).ConditionalMultiplyByTwo(i.IsOdd()).SumDigits())
                .Sum()
                .TensComplement()
            : codeWithoutChecksum
                .ToArray()
                .ToDigits(allowSymbols)
                .Select((d, i) => d.ConditionalMultiplyByTwo(i.IsEven()).SumDigits())
                .Sum()
                .TensComplement();
    }

    public static bool IsChecksumCorrect(string code, bool reverseLuhn = false, bool allowSymbols = false)
    {
        try
        {
            var checksum = code.Last().ToInt();
            return checksum == CalculateChecksum(code.Take(code.Length - 1), reverseLuhn, allowSymbols);
        }
        catch
        {
            return false;
        }
    }

    /* Be careful here. This method is probably inapropriate for anything other than its designed purpose of Luhn-algorithm based validation.
     * Specifically:
     * - numbers are assigned a value equal to the number ('0' == 0, '1' == 1).
     * - letters are assigned a value indicating the number 9 plus the letters ordinal position in the English alphabet ('A' == 10, 'B' == 11).
     * - if symbols are allowed (eg: for CUSIP validation), they are assigned values beginning from 36 ('*' == 36, '@' == 37).
     */
    private static int OrdinalPosition(this char c, bool allowSymbols = false)
    {
        if (char.IsLower(c))
            return char.ToUpper(c) - 'A' + 10;

        if (char.IsUpper(c))
            return c - 'A' + 10;

        if (char.IsDigit(c))
            return c.ToInt();

        if (allowSymbols)
            switch (c)
            {
                case '*':
                    return 36;
                case '@':
                    return 37;
                case '#':
                    return 38;
            }
        throw new ArgumentOutOfRangeException("Specified character is not a letter, digit or allowed symbol.");
    }

    private static bool IsEven(this int x)
    {
        return (x % 2 == 0);
    }

    private static bool IsOdd(this int x)
    {
        return !IsEven(x);
    }

    private static int ToInt(this char digit)
    {
        if (char.IsDigit(digit))
            return digit - '0';
        throw new ArgumentOutOfRangeException("Specified character is not a digit.");
    }

    private static IEnumerable<int> ToDigits(this char[] s, bool allowSymbols = false)
    {
        var digits = new List<int>();
        for (var i = s.Length - 1; i >= 0; i--)
        {
            var ordinalPosition = s[i].OrdinalPosition(allowSymbols);
            digits.Add(ordinalPosition % 10);
            if (ordinalPosition > 9)
                digits.Add(ordinalPosition / 10);
        }
        return digits;
    }

    private static int SumDigits(this int value)
    {
        //return value > 9 ? ((value / 10) + (value % 10)) : value;
        return ((value / 10) + (value % 10));
    }

    private static int ConditionalMultiplyByTwo(this int value, bool condition)
    {
        return condition ? value * 2 : value;
    }

    private static int TensComplement(this int value)
    {
        return (10 - (value % 10)) % 10;
    }
}

将校验和验证与正则表达式模式匹配结合使用可能是有意义的。这些是我使用的正则表达式：

ISIN：^(XS|AD|AE|AF|AG|AI|AL|AM|AO|AQ|AR|AS|AT|AU|AW|AX|AZ|BA|BB|BD|BE|BF|BG|BH|BI|BJ|BL|BM|BN|BO|BQ|BR|BS|BT|BV|BW|BY|BZ|CA|CC|CD|CF|CG|CH|CI|CK|CL|CM|CN|CO|CR|CU|CV|CW|CX|CY|CZ|DE|DJ|DK|DM|DO|DZ|EC|EE|EG|EH|ER|ES|ET|FI|FJ|FK|FM|FO|FR|GA|GB|GD|GE|GF|GG|GH|GI|GL|GM|GN|GP|GQ|GR|GS|GT|GU|GW|GY|HK|HM|HN|HR|HT|HU|ID|IE|IL|IM|IN|IO|IQ|IR|IS|IT|JE|JM|JO|JP|KE|KG|KH|KI|KM|KN|KP|KR|KW|KY|KZ|LA|LB|LC|LI|LK|LR|LS|LT|LU|LV|LY|MA|MC|MD|ME|MF|MG|MH|MK|ML|MM|MN|MO|MP|MQ|MR|MS|MT|MU|MV|MW|MX|MY|MZ|NA|NC|NE|NF|NG|NI|NL|NO|NP|NR|NU|NZ|OM|PA|PE|PF|PG|PH|PK|PL|PM|PN|PR|PS|PT|PW|PY|QA|RE|RO|RS|RU|RW|SA|SB|SC|SD|SE|SG|SH|SI|SJ|SK|SL|SM|SN|SO|SR|SS|ST|SV|SX|SY|SZ|TC|TD|TF|TG|TH|TJ|TK|TL|TM|TN|TO|TR|TT|TV|TW|TZ|UA|UG|UM|US|UY|UZ|VA|VC|VE|VG|VI|VN|VU|WF|WS|YE|YT|ZA|ZM|ZW)([0-9A-Z]{9})([0-9]{1})$

CUSIP：^[A-Z0-9]{8}[0-9]$

Answer 3

根据维基百科发布的示例，方法是：

将每个字母替换为序数（A = 1，B = 2，依此类推）加9 - ＆gt;
对于从最右边的位置（）开始的偶数位置的每个数字，将其替换为其双精度数字（两个矢量条目中的两个数字） - ＆gt; ;
验证码：

enter image description here

JavaScript中可能的实现是：

function getVerificationCode(isin)
{
 if(isin.length != 12) return null;
 var v = []; 
 for(var i = isin.length-2; i >= 0; i--)
 {
    var c = isin.charAt(i);
    if(isNaN(c)) //Not a digit
    {
        var letterCode = isin.charCodeAt(i)-55; //Char ordinal + 9
        v.push(letterCode % 10);
        if(letterCode > 9)
          v.push(Math.floor(letterCode/10));
    }
    else
      v.push(Number(c));
 }
 var sum = 0;
 var l = v.length;
 for(var i = 0; i < l; i++)
     if(i % 2 == 0)
 {
    var d = v[i]*2;
    sum += Math.floor(d/10);
    sum += d % 10;
 }
 else
    sum += v[i];
 return 10 - (sum  % 10);
}

编辑：要包含@queso更新：

function getVerificationCode(isin) {
    if (isin.length != 12) return false;
    var v = [];
    for (var i = isin.length - 2; i >= 0; i--) {
        var c = isin.charAt(i);
        if (isNaN(c)) { //not a digit
            var letterCode = isin.charCodeAt(i) - 55; //Char ordinal + 9
            v.push(letterCode % 10);
            if (letterCode > 9) {
                v.push(Math.floor(letterCode / 10));
            }
        } else {
            v.push(Number(c));
        }
    }
    var sum = 0;
    var l = v.length;
    for (var i = 0; i < l; i++) {
        if (i % 2 == 0) {
            var d = v[i] * 2;
            sum += Math.floor(d / 10);
            sum += d % 10;
        } else {
            sum += v[i];
        }
    }
    return (10 - (sum % 10)) % 10
}

Answer 4

由于 @pablo 和 @queso ，我与您分享了Matlab中的功能。

function isISIN = checkISINCode(Isin)
%
%
%
% see:
%   - source:https://en.wikipedia.org/wiki/International_Securities_Identification_Number
%   - source: https://stackoverflow.com/questions/16140753/how-to-validate-a-international-securities-identification-number-isin-number
%
%
    isISIN = 0; 

    if length(Isin) ~= 12
        return;
    end

    v = [];
    for i = (length(Isin)-1):-1:1
        c = Isin(i);
        if isnan(str2double(Isin(i)))
            % from ASCII 
            letterCode = double(upper(Isin(i))) - 64 + 9; 
            v = [mod(letterCode, 10), v];
            if letterCode > 9
                v = [floor(letterCode/10),v];
            end
        else
            v = [int8(str2double(Isin(i))), v];
        end
    end

    sum_ = 0;
    l = length(v);
    for i=1:l
        if(mod(i-1,2) == 0)
            d = v(i) * 2.;
            sum_ = sum_ + floor( double(d) / 10.0);
            sum_ = sum_ + mod(d, 10);
        else
            sum_ = sum_ + v(i);
        end
    end
    checkValue = mod((10 - mod(sum_, 10)),10);

    % Check Computed value with last digit
    isISIN = int8(str2double(Isin(end))) == checkValue;
end

Answer 5

我想在R中分享我的实现。它不需要任何特定的包。

mgsub是一个支持函数，它允许在一个命令中替换ISIN代码中的所有字符。它是从Replace multiple letters with accents with gsub

复制的

drawing layer包含Grenade列出的国家/地区列表

该算法在iso3166alpha2$Code函数中实现，在有效ISIN代码的情况下返回isIsin(x)

TRUE

Answer 6

<?php
function cusipToIsin($CUSIP, $Country)
{
    if (strlen($CUSIP) == 9) {
        $string = charToCusipBinary($Country) . charToCusipBinary($CUSIP); //Convert any letters to numbers
        $arrayString = str_split($string);
        //check wether string length is even or odd
        if (strlen($string) % 2 != 0) {
            $num = 0;
            foreach ($arrayString as $key => $value) {
                //Collect odd and even characters
                if ($key % 2 != 0) {
                    $values = $value;
                } else {
                    $values = $value * 2; //The key is in odd position, so Multiply by 2
                }
                $sumValue = array_sum(str_split($values)); //Add up the individual digits
                $num += $sumValue;
            }
            $isinCheckDigit = (10 - ($num % 10)) % 10;
            $result1 = strtoupper($Country . $CUSIP . $isinCheckDigit);
        } else {
            $num = 0;
            foreach ($arrayString as $key => $value) {
                //Collect odd and even characters
                if ($key % 2 != 0) {
                    $values = $value * 2; //The key is in even position, so Multiply by 2
                } else {
                    $values = $value;
                }
                $sumValue = array_sum(str_split($values)); //Add up the individual digits
                $num += $sumValue;
            }
            $isinCheckDigit = (10 - ($num % 10)) % 10;
            $result1 = strtoupper($Country . $CUSIP . $isinCheckDigit);
        }
        $Validate = isinValidate($result1);
        if ($Validate == true) {
            $result = $result1;
        } else {
            $result = 'Please check the CUSIP';
        }
    } else {
        $result = 'Please check the CUSIP';
    }
    return $result;
}

function charToCusipBinary($string)
{
    return strtr(strtoupper($string), ['A' => '10', 'B' => '11', 'C' => '12', 'D' => '13', 'E' => '14', 'F' => '15', 'G' => '16', 'H' => '17', 'I' => '18', 'J' => '19', 'K' => '20', 'L' => '21', 'M' => '22', 'N' => '23', 'O' => '24', 'P' => '25', 'Q' => '26', 'R' => '27', 'S' => '28', 'T' => '29', 'U' => '30', 'V' => '31', 'W' => '32', 'X' => '33', 'Y' => '34', 'Z' => '35']);
}

function isinValidate($isin)
{
    if (!preg_match('/^[A-Z]{2}[A-Z0-9]{9}[0-9]$/i', $isin)) {
        return false;
    }
    $base10 = '';
    for ($i = 0; $i <= 11; $i++) {
        $base10 .= base_convert($isin{$i}, 36, 10);
    }
    $checksum = 0;
    $len = strlen($base10) - 1;
    $parity = $len % 2;
    for ($i = $len; $i >= 0; $i--) {
        $weighted = $base10{$i} << (($i - $parity) & 1);
        $checksum += $weighted % 10 + (int) ($weighted / 10);
    }
    return !(bool) ($checksum % 10);
}

echo cusipToIsin('78012KD61', 'US'); //ISIN: US78012KD617
?>

Answer 7

这是Swift中的一种方法。

它首先检查要求的2个字母+ 10个带正则表达式的字母数字字符

func validateISIN(_ isin : String) -> Bool {
    guard isin.range(of: "^[A-Z]{2}[A-Z0-9]{10}$", options: .regularExpression) != nil,
        let checksum = Int(isin.suffix(1)) else { return false }
    let digits = isin.dropLast().map{Int(String($0), radix: 36)!}.map(String.init).joined()
    var sum = 0
    var evenFlag = true
    digits.reversed().forEach { character in
        var integer = Int(String(character))!
        if evenFlag { integer *= 2 }
        sum += integer / 10
        sum += integer % 10
        evenFlag.toggle()
    }
    return (10 - (sum % 10)) % 10 == checksum
}

Answer 8

用于验证校验和的 kotlin 版本：

fun check(isin: String): Boolean {
    val isinInts = isin.map { it.toString().toInt(36) }
        .joinToString("").map { Character.getNumericValue(it) }
    val multipliers = isinInts.indices.map { it % 2 + 1 }.reversed()
    val sum = multipliers.indices.sumOf { index: Int ->
        (isinInts[index] * multipliers[index]).let { it / 10 + it % 10 }
    }
    return (10 - (sum % 10)) % 10 == 0
}

如何验证国际证券识别号码（ISIN）号码

8 个答案: