Question

我正在编写一个简单的水果机器，这是我的方法之一，我想知道是否有可能使这个代码更有效:(在使用案例之前我有一个if / else if语句）

_intNudgeCount得到一个0到9之间的数字，因此就是这种情况。

public void DrawNudgeCount()
    {
        switch (_intNudgeCount)
        {
            case 9:
                pictureBoxNudgeCount.Image = Properties.Resources._9;
                break;
            case 8:
                pictureBoxNudgeCount.Image = Properties.Resources._8;
                break;
            case 7:
                pictureBoxNudgeCount.Image = Properties.Resources._7;
                break;
            case 6:
                pictureBoxNudgeCount.Image = Properties.Resources._6;
                break;
            case 5:
                pictureBoxNudgeCount.Image = Properties.Resources._5;
                break;
            case 4:
                pictureBoxNudgeCount.Image = Properties.Resources._4;
                break;
            case 3:
                pictureBoxNudgeCount.Image = Properties.Resources._3;
                break;
            case 2:
                pictureBoxNudgeCount.Image = Properties.Resources._2;
                break;
            case 1:
                pictureBoxNudgeCount.Image = Properties.Resources._1;
                break;
            case 0:
                pictureBoxNudgeCount.Image = Properties.Resources._0;
                break;
        }
    }

提前致谢！

解决：

没关系，我已经把它归结为3行代码：

//在类的顶部声明资源图像。

private System.Drawing.Image[]  _arrayNudgeCount;

//加载类时填充数组。

_arrayNudgeCount = new System.Drawing.Image[] { Properties.Resources._0, Properties.Resources._1};

//重绘图片

public void DrawNudgeCount()
{
pictureBoxNudgeCount.Image = _arrayNudgeCount[_intNudgeCount];
}

Answer 1

将您的图片放在应用程序旁边的文件夹中，然后调用pictureBox NudgeCount.Load（ConstantSectionPath + _intNudgeCount +“。jpg”）;如果jpg是你的文件扩展名。

Answer 2

我会把它减少到只有一行代码我就是你了！

pictureBoxNudgeCount.Image = (Image)Properties.Resources.ResourceManager.GetObject("_" + _intNudgeCount);

c＃如何使这个代码比案例场景更有效

2 个答案: