Question

我尝试将像“12000.54”这样的NSString转换为“12.000,54”。我写了一个NSNumberFormatter实例。

NSNumberFormatter *formatter = [[[NSNumberFormatter alloc] init] autorelease];
[formatter setFormatterBehavior:NSNumberFormatterBehavior10_4];
[formatter setNumberStyle:NSNumberFormatterDecimalStyle];
[formatter setGroupingSeparator:@"."];
[formatter setDecimalSeparator:@","];

但是当我NSLog这个：

NSLog(@"%@",[formatter stringFromNumber:[formatter numberFromString:value]]);

它打印空值。如果我用一个点改变我的逗号它正常工作。我只是希望能够把我想要的东西放在我的分隔符字段（逗号，点，斜线等等）中，我有不同的输出：12 / 000,54 12.000.54 12,000,54例如。

你知道我怎么处理这个吗？

Answer 1

我建议不要对分隔符进行硬编码，以确保基于iPhone区域设置的正确分隔符行为。最简单的方法是：

使用objective-c

NSNumberFormatter *numberFormatter = [[NSNumberFormatter alloc]init];
numberFormatter.locale = [NSLocale currentLocale];// this ensures the right separator behavior
numberFormatter.numberStyle = NSNumberFormatterDecimalStyle;
numberFormatter.usesGroupingSeparator = YES;

// example for writing the number object into a label
cell.finalValueLabel.text = [NSString StringWithFormat:@"%@", [numberFormatter stringForObjectValue:numberFromString]]; // your var name is not well chosen

使用SWIFT 3

 let formatter = NumberFormatter()
 formatter.locale = NSLocale.current // this ensures the right separator behavior
 formatter.numberStyle = NumberFormatter.Style.decimal
 formatter.usesGroupingSeparator = true

 // example for writing the number object into a label
 // your variable "numberFromString" needs to be a NSNumber object
 finalValueLabel.text = formatter.string(from: numberFromString)! // your var name is not well chosen

我不会使用var-name“numberFromString”，因为它是NSNumberFormatter方法。祝你好运！

Answer 2

所以问题是有效的：我自己回答：）

我从sqlite读取的十进制值（例如12000或12000.54）直接转换为NSString。我必须在代码中的某个位置使用不同的分隔符。

NSNumberFormatter *formatter = [[[NSNumberFormatter alloc] init] autorelease];
[formatter setFormatterBehavior:NSNumberFormatterBehavior10_4];
[formatter setNumberStyle:NSNumberFormatterDecimalStyle];
[formatter setGroupingSeparator:@""];
[formatter setDecimalSeparator:@"."];

// Decimal values read from any db are always written with no grouping separator and a comma for decimal.

NSNumber *numberFromString = [formatter numberFromString:@"12000.54"]];

[formatter setGroupingSeparator:@" "]; // Whatever you want here
[formatter setDecimalSeparator:@","]; // Whatever you want here

NSString *finalValue = [formatter stringFromNumber:numberFromString];

NSLog(@"%@",finalValue); // Print 12 000,54

问题解决了。

Answer 3

我最近发现的最简单的解决方案是：

NSString *localizedString = [NSString localizedStringWithFormat:@"%@", @1234567];

也适用于整数：

NSString *localizedString = [NSString localizedStringWithFormat:@"%d", 1234567];

在Xcode 6游乐场验证。但是医生说这个功能一直存在。

Answer 4

NSNumberFormatter *numberFormatter = [[NSNumberFormatter alloc] init];
[numberFormatter setNumberStyle:NSNumberFormatterDecimalStyle];
numberFormatter.usesGroupingSeparator = YES;
[numberFormatter setMaximumFractionDigits:2];
[numberFormatter setMinimumFractionDigits:2];
NSString *formattedNumberString = [numberFormatter stringFromNumber:@122344.00];`

如果您处理小数点，这将解决您的舍入问题。

Answer 5

货币用途......

let numberFormatter = NumberFormatter()

// Produces symbol (i.e. "$ " for en_US_POSIX) and decimal formatting
numberFormatter.numberStyle = .currency

// Produces commas; i.e. "1,234"
numberFormatter.usesGroupingSeparator = true
numberFormatter.groupingSize = 3

使用示例：

let value: Double = 12345.6789
numberFormatter.string(from: value as NSNumber)

...产量

"$ 12,345.68"

正如人们所期望的那样

带逗号小数分隔符的NSNumberFormatter

5 个答案: