Question

这里是java中的tic tac toe游戏，有人可以完成程序，它将保存多少次赢取X和文本文件中的O多少次，请：）

    package xo2;


    import java.awt.*;
    import java.awt.event.*;
    import javax.swing.*;

public class XO2 implements ActionListener {


    private int[][] winningCombination = new int[][] {
            {0, 1, 2},
                        {3, 4, 5},
                        {6, 7, 8}, 
            {0, 3, 6},
                        {1, 4, 7},
                        {2, 5, 8}, 
            {0, 4, 8},
                        {3, 4, 6}            
    };
    private JFrame window = new JFrame("Tic Tac Toe");
    private JButton buttons[] = new JButton[9];
    private int count = 0;
    private String letter = "";
    private boolean win = false;

    public XO2(){

        window.setSize(300,300);
        window.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
        window.setLayout(new GridLayout(3,3));


        for(int i=0; i<9; i++){
            buttons[i] = new JButton();
            window.add(buttons[i]);
            buttons[i].addActionListener(this);
        }


        window.setVisible(true);
    }

    public void actionPerformed(ActionEvent a) {
        count++;


        if(count % 2 == 0){
            letter = "O";
        }
        else {
            letter = "X";
        }

        JButton pressedButton = (JButton)a.getSource();
        pressedButton.setText(letter);
        pressedButton.setEnabled(false);


        for(int i=0; i<8; i++){
            if( buttons[winningCombination[i][0]].getText().equals(buttons[winningCombination[i][1]].getText()) &&
                    buttons[winningCombination[i][1]].getText().equals(buttons[winningCombination[i][2]].getText()) &&
                    !buttons[winningCombination[i][0]].getText().equals("")){
                win = true;
            }
        }

        if(win == true){
            JOptionPane.showMessageDialog(null, letter + " won!");
            System.exit(0);
        } else if(count == 9 && win == false){
            JOptionPane.showMessageDialog(null, "draw!");
            System.exit(0);
        }
    }

    public static void main(String[] args){
        XO2 starter = new XO2();
    }
}

Answer 1

我为你创建了一个基本类，它将胜利保存到文本文件中并从文本文件中检索它们。

import java.io.File;
import java.io.FileNotFoundException;
import java.io.PrintWriter;
import java.util.Scanner;

public class WinsFileManager {

    String path = System.getProperty("user.home").replace("\\", "\\\\") + "\\";

    public int getWins(String fileName) {

        String fullPath = path + fileName;
        int wins = 0;

        try {
            wins = Integer.parseInt(new Scanner(new File(fullPath)).nextLine());
        } catch (NumberFormatException e) {} 
          catch (FileNotFoundException e) {
            wins = 0;
        }

        return wins;
    }

    public void saveWins(String fileName, int wins) {
        PrintWriter out = null;

        try {
            out = new PrintWriter(path + fileName, "UTF-8");
            out.println(wins);
            out.close();
        } catch (Exception e) {
            e.printStackTrace();
        }
    }
}

以下是您从不同位置使用上述类的对象的方法。

public class test {

    public static void main(String[] args) {
        WinsFileManager manager = new WinsFileManager();
        String fileName = "O Wins.txt";

        manager.saveWins(fileName, 5);
        System.out.println(manager.getWins(fileName));
    }
}

上例中的控制台输出为'5'。

我做了很多困难。现在由您决定将其实施到您的程序中。首先，每当有人获胜时，我将通过getWins方法检索存储的获胜次数，向该值添加一个，然后使用saveWins方法存储递增的值。请记住，即使退出程序，也会保存获胜值。

注意：如果你想要做的就是在程序的生命周期内跟踪胜利，那么有更简单的方法可以做到这一点。

Answer 2

查看以下资源。

Reading and writing a text file.

How to write console output to a txt file.

How do I create and write data into a text file?

如何将游戏结果保存到文本文件中

2 个答案: