preg_replace不忽略字符串中的[]

Question

这是我的代码：

$string = "Hello this is my text [readmore] and this is remaining text";
echo preg_replace("[readmore]","",$string);

这是我的预期输出：

Hello this is my text and this is remaining text

这是我的实际输出：

Hello this is my text [] and this is remaining text

问题很简单，如何乘坐“[]”？

Answer 1

你需要逃避[＆amp; ]。请尝试以下regexp，

preg_replace("/\[([^\[\]]++|(?R))*+\]/", "", $string);

<强>输出：

Hello this is my text and this is remaining text

CodePad Demo.

Answer 2

您需要转义括号以在正则表达式中使用。此外，您可能需要查看preg_replace的手册，因为您已经离开了需要围绕正则表达式的/。

$string = "Hello this is my text [readmore] and this is remaining text";
echo preg_replace("/\[readmore\]/","",$string);

Answer 3

转义'['和']'字符：

这个脚本：

 $string = "Hello this is my text [readmore] and this is remaining text";
 echo preg_replace("[\\[readmore\\] ]","",$string);

这个结果（我对此进行了测试）：

 Hello this is my text and this is remaining text     

Answer 4

使用str_replace

$string = "Hello this is my text [readmore] and this is remaining text";
echo str_replace("[readmore]","",$string);

<强>输出

Hello this is my text and this is remaining text