在我的系统中,我正在运行apache_tomcat_6.0,但我在E盘中设置了apache_tomcat_6.0.18的文件,我从E盘中获取了startup.bat文件,所以在执行以下代码时出现错误
ssssssssssss:java.lang.ProcessImpl@19e3cd51
E:/nymble/Nymble/code/apache-tomcat-6.0.18/bin/startup.bat返回0
private void downloadActionPerformed(java.awt.event.ActionEvent evt)
{
Runtime r = Runtime.getRuntime();
Process p = null;
String cmd = "E:/nymble/Nymble/code/apache-tomcat-6.0.18/bin/startup.bat";
try {
p = r.exec(cmd);
p.waitFor();
}
catch (Exception e)
{
System.out.println("error executing " + cmd);
}
System.out.println("ssssssssssss : "+p);
System.out.println(cmd + " returned "+ p.exitValue());
}