在这个例子中,我有一个嵌套模板来显示树状视图,如缩进输出,但叶子节点上呈现的HTML不是我所期望的。如何让叶子节点呈现预期的html并且不包含子容器div?
如果我将if绑定放在模板绑定之外,我会收到一个javascript错误:
Uncaught Error: Multiple bindings (if and template) are trying to control descendant bindings of the same element. You cannot use these bindings together on the same element.
注意:使用if绑定注释<!-- ko if: children().length > 0 -->
确实可以删除不需要的元素,但是生成的html充满了注释,我宁愿保持干净,因为我可能有数百个叶子节点
我尝试过使用2个模板,一个用于容器,另一个没有,并且为名称添加条件,但模板始终呈现nodeTempl:data-bind="template: { name: (children().length > 0) ? 'nodeTempl' : 'leafTempl', foreach: children }"
我想我真的想根据当前正在处理的孩子的状态来应用不同的模板。
叶子节点正在像这样呈现
<div>
<div data-bind="text: name">Node 1-1-1</div>
<div class="indent-1" data-bind="template: {if: children().length > 0, name: 'nodeTempl', foreach: children }"></div>
</div>
但是我希望它像这样呈现:
<div>
<div data-bind="text: name">Node 1-1-1</div>
</div>
以下是设置:
HTML
<style type="text/css">
.indent-1 {
margin-left: 20px;
}
</style>
<script id="nodeTempl" type="text/html">
<div>
<div data-bind="text: name"></div>
<div class="indent-1" data-bind="template: {if: children().length > 0, name: 'nodeTempl', foreach: children }"></div>
</div>
</script>
<div data-bind="template: { name: 'nodeTempl', foreach: children }"></div>
脚本
var node = function (config) {
var self = this;
self.name = ko.observable(config.name);
self.children = ko.observableArray([]);
if ($.isArray(config.children)) {
for (var i = 0; i < config.children.length; i++) {
self.children.push(new node(config.children[i]));
}
}
};
ko.applyBindings(new node(
{
name: 'root',
children: [
{ name: 'Node1', children: [{name: 'Node 1-1', children: [{name: 'Node 1-1-1'}]},{name: 'Node 1-2'}]},
{name: 'Node2',children: [{name: 'Node 2-1'},{name: 'Node 2-2'}]},
{name: 'Node3'},
]
}
));
输出
<div data-bind="template: { name: 'nodeTempl', foreach: children }">
<div>
<div data-bind="text: name">Node1</div>
<div class="indent-1" data-bind="template: {if: children().length > 0, name: 'nodeTempl', foreach: children }">
<div>
<div data-bind="text: name">Node 1-1</div>
<div class="indent-1" data-bind="template: {if: children().length > 0, name: 'nodeTempl', foreach: children }">
<div>
<div data-bind="text: name">Node 1-1-1</div>
<div class="indent-1" data-bind="template: {if: children().length > 0, name: 'nodeTempl', foreach: children }"></div>
</div>
</div>
</div>
<div>
<div data-bind="text: name">Node 1-2</div>
<div class="indent-1" data-bind="template: {if: children().length > 0, name: 'nodeTempl', foreach: children }"></div>
</div>
</div>
</div>
<div>
<div data-bind="text: name">Node2</div>
<div class="indent-1" data-bind="template: {if: children().length > 0, name: 'nodeTempl', foreach: children }">
<div>
<div data-bind="text: name">Node 2-1</div>
<div class="indent-1" data-bind="template: {if: children().length > 0, name: 'nodeTempl', foreach: children }"></div>
</div>
<div>
<div data-bind="text: name">Node 2-2</div>
<div class="indent-1" data-bind="template: {if: children().length > 0, name: 'nodeTempl', foreach: children }"></div>
</div>
</div>
</div>
<div>
<div data-bind="text: name">Node3</div>
<div class="indent-1" data-bind="template: {if: children().length > 0, name: 'nodeTempl', foreach: children }"></div>
</div>
</div>
答案 0 :(得分:7)
您走在正确的轨道上,建议您需要两个模板。模板name
参数可以是返回数组中每个项的模板名称的函数。
您可以创建如下函数:
function nodeTemplate(node) {
return node.children().length > 0 ? 'nodeTempl' : 'nodeLeafTempl';
}
并将您的观点改为:
<script id="nodeTempl" type="text/html">
<div>
<div data-bind="text: name"></div>
<div class="indent-1" data-bind="template: {name: nodeTemplate, foreach: children }"></div>
</div>
</script>
<script id="nodeLeafTempl" type="text/html">
<div>
<div data-bind="text: name"></div>
</div>
</script>
<div data-bind="template: { name: nodeTemplate, foreach: children }"></div>