使用位图对我来说是一个非常新的事情,所以我一直在努力学习我读过的在线教程和策略。基本上我的目标是扫描屏幕上的特定RGB值。我相信这样做的步骤是捕获hBitmap中的屏幕,然后从中生成一个我可以扫描的RGB值数组。
我最初是从GetPixel开始的,但这很慢。解决方案是使用GetDIBits生成RGB值数组。问题是它会返回奇怪的,可能是随机的RGB值。
我正在使用以下代码,我在其他教程中找到了这些代码:
/* Globals */
int ScreenX = GetDeviceCaps(GetDC(0), HORZRES);
int ScreenY = GetDeviceCaps(GetDC(0), VERTRES);
BYTE* ScreenData = new BYTE[3*ScreenX*ScreenY];
void ScreenCap() {
HDC hdc = GetDC(GetDesktopWindow());
HDC hdcMem = CreateCompatibleDC (hdc);
HBITMAP hBitmap = CreateCompatibleBitmap(hdc, ScreenX, ScreenY);
BITMAPINFOHEADER bmi = {0};
bmi.biSize = sizeof(BITMAPINFOHEADER);
bmi.biPlanes = 1;
bmi.biBitCount = 24;
bmi.biWidth = ScreenX;
bmi.biHeight = -ScreenY;
bmi.biCompression = BI_RGB;
bmi.biSizeImage = ScreenX * ScreenY;
SelectObject(hdcMem, hBitmap);
BitBlt(hdcMem, 0, 0, ScreenX, ScreenY, hdc, 0, 0, SRCCOPY);
GetDIBits(hdc, hBitmap, 0, ScreenY, ScreenData, (BITMAPINFO*)&bmi, DIB_RGB_COLORS);
DeleteDC(hdcMem);
ReleaseDC(NULL, hdc);
}
inline int PosR(int x, int y) {
return ScreenData[3*((y*ScreenX)+x)+2];
}
inline int PosG(int x, int y) {
return ScreenData[3*((y*ScreenX)+x)+1];
}
inline int PosB(int x, int y) {
return ScreenData[3*((y*ScreenX)+x)];
}
我使用以下代码测试它。我按Shift键调用ScreenCap,然后将光标移动到所需位置,然后点击Space查看该位置的RGB值。我完全疯了吗?
int main() {
while ( true ) {
if (GetAsyncKeyState(VK_SPACE)){
// Print out current cursor position
GetCursorPos(&p);
printf("X:%d Y:%d \n",p.x,p.y);
// Print out RGB value at that position
int r = PosR(p.x, p.y);
int g = PosG(p.x, p.y);
int b = PosB(p.x, p.y);
printf("r:%d g:%d b:%d \n",r,g,b);
} else if (GetAsyncKeyState(VK_ESCAPE)){
printf("Quit\n");
break;
} else if (GetAsyncKeyState(VK_SHIFT)){
ScreenCap();
printf("Captured\n");
}
}
system("PAUSE");
return 0;
}
答案 0 :(得分:8)
问题是你的屏幕实际上是32位深度而不是24位。下面的代码将为您提供所需的结果:
/* Globals */
int ScreenX = 0;
int ScreenY = 0;
BYTE* ScreenData = 0;
void ScreenCap()
{
HDC hScreen = GetDC(GetDesktopWindow());
ScreenX = GetDeviceCaps(hScreen, HORZRES);
ScreenY = GetDeviceCaps(hScreen, VERTRES);
HDC hdcMem = CreateCompatibleDC (hScreen);
HBITMAP hBitmap = CreateCompatibleBitmap(hScreen, ScreenX, ScreenY);
HGDIOBJ hOld = SelectObject(hdcMem, hBitmap);
BitBlt(hdcMem, 0, 0, ScreenX, ScreenY, hScreen, 0, 0, SRCCOPY);
SelectObject(hdcMem, hOld);
BITMAPINFOHEADER bmi = {0};
bmi.biSize = sizeof(BITMAPINFOHEADER);
bmi.biPlanes = 1;
bmi.biBitCount = 32;
bmi.biWidth = ScreenX;
bmi.biHeight = -ScreenY;
bmi.biCompression = BI_RGB;
bmi.biSizeImage = 0;// 3 * ScreenX * ScreenY;
if(ScreenData)
free(ScreenData);
ScreenData = (BYTE*)malloc(4 * ScreenX * ScreenY);
GetDIBits(hdcMem, hBitmap, 0, ScreenY, ScreenData, (BITMAPINFO*)&bmi, DIB_RGB_COLORS);
ReleaseDC(GetDesktopWindow(),hScreen);
DeleteDC(hdcMem);
DeleteObject(hBitmap);
}
inline int PosB(int x, int y)
{
return ScreenData[4*((y*ScreenX)+x)];
}
inline int PosG(int x, int y)
{
return ScreenData[4*((y*ScreenX)+x)+1];
}
inline int PosR(int x, int y)
{
return ScreenData[4*((y*ScreenX)+x)+2];
}
bool ButtonPress(int Key)
{
bool button_pressed = false;
while(GetAsyncKeyState(Key))
button_pressed = true;
return button_pressed;
}
int main()
{
while (true)
{
if (ButtonPress(VK_SPACE))
{
// Print out current cursor position
POINT p;
GetCursorPos(&p);
printf("X:%d Y:%d \n",p.x,p.y);
// Print out RGB value at that position
std::cout << "Bitmap: r: " << PosR(p.x, p.y) << " g: " << PosG(p.x, p.y) << " b: " << PosB(p.x, p.y) << "\n";
} else if (ButtonPress(VK_ESCAPE))
{
printf("Quit\n");
break;
} else if (ButtonPress(VK_SHIFT))
{
ScreenCap();
printf("Captured\n");
}
}
system("PAUSE");
return 0;
}
答案 1 :(得分:0)
您的图片尺寸以像素指定,应以字节
指定**bmi.biSizeImage = ScreenX * ScreenY;**
**bmi.biBitCount = 24;**
bmi.biWidth = ScreenX;
bmi.biHeight = -ScreenY;
**bmi.biCompression = BI_RGB;**
biSizeImage 其定义的单位为字节,您指定每像素RGB 3个字节。
http://msdn.microsoft.com/en-us/library/windows/desktop/dd183376(v=vs.85).aspx
biSizeImage 图像的大小(字节)。对于BI_RGB位图,这可以设置为零。