这是我的问题:
我的设备上有一个float3
的3D数组:
int size[3] = {416,464,512};
cudaExtent extent = make_cudaExtent(size[0]*sizeof(float3),size[1],size[2]);
cudaPitchedPtr renderedVolume;
int ret = cudaMalloc3D(&renderedVolume, extent);
size_t pitch = renderedVolume.pitch; //pitch = 5,120
size_t slicePitch = pitch * size[1]; //slicePitch = 2,375,680
然后我使用它并使其充满了出色的数据。
之后,我希望将其复制到主机上的1D线性内存中:
float *host_memory = (float*)malloc(size[0]*size[1]*size[2]*sizeof(float3));
cudaMemcpy3DParms p = {0};
p.srcPtr = renderedVolume;
p.dstPtr = make_cudaPitchedPtr(host_memory,size[0]*sizeof(float3),size[0],size[1]);
p.extent = make_cudaExtent(size[0]*sizeof(float3),size[1],size[2]);
p.srcPos = make_cudaPos(0,0,0);
p.dstPos = make_cudaPos(0,0,0);
p.kind=cudaMemcpyDeviceToHost;
cudaMemcpy3D(&p);
我将host_memory中的结果与我最初编写的数据renderedVolume
(my_data
)以及我在3Dmemory
中读取的数据进行比较,逐片切换:
float* test1 = (float*)malloc(size[0]*size[1]*sizeof(float3));
cudaMemcpy(test1, myData, size[0]*size[1]*sizeof(float3) , cudaMemcpyDeviceToHost);
float* test2 = (float*)malloc(size[0]*size[1]*sizeof(float3));
cudaMemcpy(test2,(char*)renderedVolume.ptr + slicePitch * i,size[0]*size[1]*sizeof(float3), cudaMemcpyDeviceToHost);
问题:
i=0
)没问题,我在host_memory中有相同的数据,test1
和test2
。test1
和test2
中拥有相同的数据。但是,我应该在host_memory+579072
(=每个切片float
的数量,也是目标投标指针的heigth*pitch
)中找到此数据,并在host_memory+577504
中找到它。它被1568
字节关闭,这对应于我所知道的任何内容,这就是为什么我非常感谢你们中的任何一个人知道我的代码中可能存在什么问题?答案 0 :(得分:4)
这是一个迟到的答案,用于从未答复的列表中删除此问题。
下面,我提供了一个完整的代码,展示了如何通过3D
分配cudaMalloc3D
内存,将主机分配的1D
内存移动到3D
设备内存cudaMemcpy3D
,3D
test_kernel_3D
函数对__global__
设备数据执行某些操作,并将3D
结果数据移回1D
主机内存,再次由cudaMemcpy3D
。
__global__
函数test_kernel_3D
平方3D
设备内存的每个元素。特别是,2D
网格的每个线程负责沿着"深度"执行for
循环。尺寸。
#include<stdio.h>
#include<cuda.h>
#include<cuda_runtime.h>
#include<device_launch_parameters.h>
#include<conio.h>
#define BLOCKSIZE_x 16
#define BLOCKSIZE_y 16
#define N 128
#define M 64
#define W 16
/*****************/
/* CUDA MEMCHECK */
/*****************/
#define gpuErrchk(ans) { gpuAssert((ans), __FILE__, __LINE__); }
inline void gpuAssert(cudaError_t code, char *file, int line, bool abort=true)
{
if (code != cudaSuccess)
{
fprintf(stderr,"GPUassert: %s %s %d\n", cudaGetErrorString(code), file, line);
if (abort) { getch(); exit(code); }
}
}
/*******************/
/* iDivUp FUNCTION */
/*******************/
int iDivUp(int a, int b){ return ((a % b) != 0) ? (a / b + 1) : (a / b); }
/******************/
/* TEST KERNEL 3D */
/******************/
__global__ void test_kernel_3D(cudaPitchedPtr devPitchedPtr)
{
int tidx = blockIdx.x*blockDim.x+threadIdx.x;
int tidy = blockIdx.y*blockDim.y+threadIdx.y;
char* devPtr = (char*) devPitchedPtr.ptr;
size_t pitch = devPitchedPtr.pitch;
size_t slicePitch = pitch * N;
for (int w = 0; w < W; w++) {
char* slice = devPtr + w * slicePitch;
float* row = (float*)(slice + tidy * pitch);
row[tidx] = row[tidx] * row[tidx];
}
}
/********/
/* MAIN */
/********/
int main()
{
float a[N][M][W];
for (int i=0; i<N; i++)
for (int j=0; j<M; j++)
for (int w=0; w<W; w++) {
a[i][j][w] = 3.f;
//printf("row %i column %i depth %i value %f \n",i,j,w,a[i][j][w]);
}
// --- 3D pitched allocation and host->device memcopy
cudaExtent extent = make_cudaExtent(M * sizeof(float), N, W);
cudaPitchedPtr devPitchedPtr;
gpuErrchk(cudaMalloc3D(&devPitchedPtr, extent));
cudaMemcpy3DParms p = { 0 };
p.srcPtr.ptr = a;
p.srcPtr.pitch = M * sizeof(float);
p.srcPtr.xsize = M;
p.srcPtr.ysize = N;
p.dstPtr.ptr = devPitchedPtr.ptr;
p.dstPtr.pitch = devPitchedPtr.pitch;
p.dstPtr.xsize = M;
p.dstPtr.ysize = N;
p.extent.width = M * sizeof(float);
p.extent.height = N;
p.extent.depth = W;
p.kind = cudaMemcpyHostToDevice;
gpuErrchk(cudaMemcpy3D(&p));
dim3 GridSize(iDivUp(M,BLOCKSIZE_x),iDivUp(N,BLOCKSIZE_y));
dim3 BlockSize(BLOCKSIZE_y,BLOCKSIZE_x);
test_kernel_3D<<<GridSize,BlockSize>>>(devPitchedPtr);
gpuErrchk(cudaPeekAtLastError());
gpuErrchk(cudaDeviceSynchronize());
p.srcPtr.ptr = devPitchedPtr.ptr;
p.srcPtr.pitch = devPitchedPtr.pitch;
p.dstPtr.ptr = a;
p.dstPtr.pitch = M * sizeof(float);
p.kind = cudaMemcpyDeviceToHost;
gpuErrchk(cudaMemcpy3D(&p));
for (int i=0; i<N; i++)
for (int j=0; j<M; j++)
for (int w=0; w<W; w++)
printf("row %i column %i depth %i value %f\n",i,j,w,a[i][j][w]);
getch();
return 0;
}