Question

我们收到的数据格式如下：

'1:0,2:1,3:1,4:0'

值以逗号分隔：冒号前面的值是studentId，后面是位值。

我想将这些值存储在临时表中：

studentID   |   BitValue
1           |    0
2           |    1
3           |    1
4           |    0

如何在SQL Server 2005中执行此操作？

Answer 1

这适用于 MS SQL Server 2008 。

IF OBJECT_ID('tempdb..#TempTable') IS NOT NULL 
drop table #TempTable

create table #TempTable (studentID int, BitValue int)
declare @var nvarchar(max)
set @var='1:0,2:1,3:1,4:0'

set @var='insert into #TempTable values ('+REPLACE(REPLACE(@var,',','),('), ':', ',')+')'
exec (@var)

select * from #TempTable

drop table #TempTable

MS SQL Server 2005 ，请尝试：

IF OBJECT_ID('tempdb..#TempTable') IS NOT NULL 
drop table #TempTable

create table #TempTable (studentID int, BitValue int)
declare @var nvarchar(max)
set @var='1:0,2:1,3:1,4:0'

--set @var=REPLACE(@var,',','),(')
set @var='insert into #TempTable values ('+REPLACE(REPLACE(@var,',','); insert into #TempTable values('), ':', ',')+')'
exec (@var)

select * from #TempTable

drop table #TempTable

Answer 2

试试这个

DECLARE @param NVARCHAR(MAX)

SET @param = '1:0,2:1,3:1,4:0'

;WITH Split_Col 
AS
(
    SELECT CONVERT(XML,'<table><col>' + REPLACE(ColName,':', '</col><col>') + '</col></table>') AS xmlcol
    FROM
    (
        SELECT Split.a.value('.', 'VARCHAR(100)') AS ColName  
        FROM  
        (
             SELECT CAST ('<M>' + REPLACE(ColName, ',', '</M><M>') + '</M>' AS XML) AS ColName  
             FROM  (SELECT @param AS ColName) TableName
         ) AS A CROSS APPLY ColName.nodes ('/M') AS Split(a)
    ) TableName
)

 SELECT      
 xmlcol.value('/table[1]/col[1]','varchar(100)') AS studentID,    
 xmlcol.value('/table[1]/col[2]','varchar(100)') AS BitValue
 FROM Split_Col

修改

假设您的学生表有列StudentId，Name。找到加入学生表的更新查询

SELECT ST.Name,SP.studentID,SP.BitValue FROM ( SELECT xmlcol.value('/table[1]/col[1]','varchar(100)') AS studentID, xmlcol.value('/table[1]/col[2]','varchar(100)') AS BitValue FROM Split_Col ) SP INNER JOIN Student ST on SP.studentID = ST.studentID

SQLFiddle Demo

使用逗号记录分隔符和冒号分隔的名称 - 值对从字符串中插入SQL行

2 个答案: