我有两张桌子
表1类别
Id name img
1 appliances
2 books
表2产品
ID name des price cataegory sub img
1 TV lcd 125 1 tv
我正在尝试加入表2中类别中的两个表,直到从表1中获取名称
这是我的代码
$sql = "SELECT p.id,
p.name,
p.description,
p.price,
c.name,
p.sub
FROM products p
JOIN category c on products p = c.id
ORDER by p.id
";
if($query = mysql_query($sql) or die())
{
while($result = mysql_fetch_assoc($query))
{ echo "<tr id='id'>";
//echo "<td>".$result['img']."</td>";
echo "<td>".$result['name']."</td>";
echo "<td>".$result['description']."</td>";
echo "<td>".$result['price']."</td>";
echo "<td>".$result['category']."</td>";
echo "<td>".$result['sub']."</td>";
echo "</tr>";
}
} ";
答案 0 :(得分:1)
将类别名称添加到select query:
返回的列中$sql = "SELECT p.id,
p.name,
p.description,
p.price,
c.name,
p.sub,
c.name AS category_name -- Category name
FROM products p
JOIN category c on p.category = c.id
ORDER by p.id
";
答案 1 :(得分:1)
在输出中重命名字段名称:
$sql = "SELECT p.id,
p.name,
p.description,
p.price,
c.name AS OTHER_NAME,
p.sub
FROM products p
JOIN category c on p.category = c.id
ORDER by p.id";
然后获取 OTHER_NAME
答案 2 :(得分:0)
$sql = "SELECT p.id,
p.name,
p.description,
p.price,
c.name,
p.sub
FROM products p
JOIN category c on p.cataegory = c.id
ORDER by p.id
";
答案 3 :(得分:0)
您的查询应该是这样的
SELECT
p.id,
p.name,
p.description,
p.price,
c.name,
p.sub
FROM products p
INNER JOIN c.category
on products p.cataegory = c.id
ORDER by p.id
使用内部联接获取特定结果