Question

我有示例数据

SMMP022011304196
SMMP022011304199    
SMMP022011304197    
SMMP022011304193
SMMP022011304195    
SMMP022011304198    
SMMP022011304192    
SMMP0220113041910   
SMMP022011304191
SMMP022011304194

如果我使用SELECT myfield from mytable order by myfield DESC 我得到了这样的结果

SMMP022011304199    
SMMP022011304198    
SMMP022011304197    
SMMP022011304196    
SMMP022011304195    
SMMP022011304194    
SMMP022011304193    
SMMP022011304192    
SMMP0220113041910   
SMMP022011304191

请帮助制作这样的结果：

SMMP0220113041910   
SMMP022011304199    
SMMP022011304198    
SMMP022011304197    
SMMP022011304196    
SMMP022011304195    
SMMP022011304194    
SMMP022011304193    
SMMP022011304192    
SMMP022011304191

Answer 1

按字段的LENGTH排序，然后按长度相等的值排序：

SELECT myfield from mytable order by 
LENGTH(myfield) DESC,
myfield DESC

SQLFiddle demo

Answer 2

如果数据总是在前面有SMMP，您可以使用以下内容：

ORDER BY LPAD(REPLACE(myfield,'SMMP',''),15,'0') desc;

这种方法的逻辑是忽略前面的4个字符，只对后面的数字进行排序。

Answer 3

按照我之前的评论，排序如下： -

SELECT myfield
FROM mytable
ORDER BY SUBSTRING(myfield, 1, 4) DESC, cast(SUBSTRING(myfield, 5) AS unsigned) DESC

请注意，这仅适用于您的字段是固定格式，其中包含4个字符后跟数字

Answer 4

这很好用。下面的代码适用于SQL Server 2008 R2：

SELECT 
   myfield  
FROM mytable 
ORDER BY 
    LEN(myfield) DESC 
    ,myfield DESC

选择查询字符数字id按顺序排序

4 个答案: