Question

我有这样的字符串集。

1 Wednesday, 3 Monday, 1 2 Tuesday

现在我需要只考虑字母来排序这些。结果将是

3 Monday, 1 2 Tuesday, 1 Wednesday

通过考虑子串（星期三，星期一，星期二）对字符串进行排序，因此得到了结果。我怎么能这样做？

Answer 1

使用compareOptions，在选项中删除kCFCompareNumerically。

参见下一个网址： Sorting Strings

或试试这个：

#import <Foundation/Foundation.h>

int main (int argc, const char * argv[]) {

@autoreleasepool {

    NSArray *stringsArray = [NSArray arrayWithObjects:
                             @"string 1",
                             @"String 21",
                             @"string 12",
                             @"String 11",
                             @"String 02", nil];
    static NSStringCompareOptions comparisonOptions = NSCaseInsensitiveSearch |
    NSWidthInsensitiveSearch | NSForcedOrderingSearch;
    NSLocale *currentLocale = [NSLocale currentLocale];
    NSComparator finderSort = ^(id string1, id string2) {
        NSRange string1Range = NSMakeRange(0, [string1 length]);
        return [string1 compare:string2 options:comparisonOptions range:string1Range locale:currentLocale];
    };

    NSArray* sortedArray = [stringsArray sortedArrayUsingComparator:finderSort];
    NSLog(@"finderSort: %@", sortedArray);        
    }
    return 0;
}

Answer 2

尝试

NSArray *array = @[@"1 Wednesday",@"3 Monday",@"1 2 Tuesday"];

NSDateFormatter *dateFormatter = [[NSDateFormatter alloc]init];
[dateFormatter setDateFormat:@"EEEEE"];

NSArray *sortedArray = [array sortedArrayUsingComparator:^NSComparisonResult(id obj1, id obj2) {
    NSCharacterSet *validCharacterSet = [NSCharacterSet letterCharacterSet];
    NSCharacterSet *unwantedCharecterSet = [validCharacterSet invertedSet];
    NSString *string1 = [(NSString *)obj1 stringByTrimmingCharactersInSet:unwantedCharecterSet];
    NSString *string2 = [(NSString *)obj2 stringByTrimmingCharactersInSet:unwantedCharecterSet];

    NSDate *date1 = [dateFormatter dateFromString:string1];
    NSDate *date2 = [dateFormatter dateFromString:string2];

    return [date1 compare:date2];

}];

（适用 “3星期一”， “1 2星期二”， “1星期三” ）

Answer 3

或者，如果要排序的字符串总是最后一个字符串（并且总是是最后一个字符串），您可以编写一个对其进行排序的比较器最后一个字符串：

NSComparator lastStringSort = ^(id string1, id string2)
{
    NSArray* string1Components = [string1 componentsSeparatedByString:@" "];
    NSArray* string2Components = [string2 componentsSeparatedByString:@" "];
    return [[string1Components lastObject] compareToString:[string2Components lastObject]];
};

NSArray* sortedArray = [stringsArray sortedArrayUsingComparator:lastStringSort];

对包含数字和字符的字符串进

3 个答案: