Question

 SELECT *
 FROM   [Live].[Test]
 WHERE  [_fk_RoadMapKey] = @_fk_RoadMapKey

 SELECT @TestKey = [TestKey]
 FROM   [Live].[Test]
 WHERE  [_fk_RoadMapKey] = @_fk_RoadMapKey

 SELECT *
 FROM   [Live].[SetofTestGrades]
 WHERE  [_fk_TestKey] = @TestKey

前两个语句，我们可以在分配testkey的同时进行所有测试吗

SELECT * ,@TestKey = [TestKey] FROM [Live].[Test]
    WHERE [_fk_RoadMapKey] = @_fk_RoadMapKey

Answer 1

您不能使用单个select语句将数据分配给变量并返回数据，如果您使用@TestKey从另一个表中检索值，那么您可以跳过变量并使用join从另一个表中获取数据，尝试此

 SELECT *
 FROM   [Live].[Test]
 WHERE  [_fk_RoadMapKey] = @_fk_RoadMapKey

 SELECT S.*
 FROM  [Live].[SetofTestGrades] S 
 INNER JOIN [Live].[Test] T ON S.[_fk_TestKey]  = T.[TestKey]
 WHERE  t.[_fk_RoadMapKey] = @_fk_RoadMapKey

语法将两个存储过程合并为一个

1 个答案: