Question

我有一份报告，根据我们的业务规则显示重复帐户的列表。当一个新帐户与其他现有帐户匹配时，此方法有效。我遇到麻烦的地方是多个新帐户匹配相同的现有副本。这是一个现在看起来如何的例子，按NewId分组：

NewID   MatchedID   FirstName   LastName    AddDate      Address        PhoneNumber
10      10          Holly       Johnson     4/18/2013    123 1St Rd.    123 456 7890
10      2           Hollie      Johnson     1/1/1990     123 1St Rd.    123 456 7890

11      11          Holley      Johnson     4/17/2013    123 1St Rd.    123-456-7890
11      2           Hollie      Johnson     1/1/1990     123 First Rd.  123 456 7890

50      50          William     Johnson     4/17/2013    999 2nd St.    222 222 2222
50      3           Bill        Jonson      1/2/1990     999 Second St. 222-222-2222

具有匹配项的帐户本身也包含在内以供比较。

那么，有没有办法将这些类似的帐户组合在一起而不重复？它应该是这样的：

GroupID  AcctID   FirstName   LastName    AddDate      Address        PhoneNumber
1        2        Hollie      Johnson     1/1/1990     123 First Rd.  123 456 7890
1        10       Holly       Johnson     4/18/2013    123 1St Rd.    123 456 7890
1        11       Holley      Johnson     4/17/2013    123 1St Rd.    123-456-7890
2        50       William     Johnson     4/17/2013    999 2nd St.    222 222 2222
2        3        Bill        Jonson      1/2/1990     999 Second St. 222-222-2222

我不关心分组是在SQL中还是在SSRS中完成的。它需要引用两个ID列，因为名称，地址和电话号码可能不同。我还需要分配一个新的GroupID，以便将它们分组到报告中。

Answer 1

您可以使用排名功能来消除行：

with NoDuplicates as
(
  select *
    , rownum = row_number() over (partition by MatchedID order by NewID)
  from Accounts
)
select   NewID
  , MatchedID
  , Name
  , AddDate
  , Address
  , phoneNumber
from NoDuplicates where rownum = 1

SQL Fiddle with demo

虽然没有理由你不能只使用GROUP BY假设地址信息也总是重复：

select NewID = min(NewID)
  , MatchedID
  , Name
  , AddDate
  , Address
  , phoneNumber
from Accounts
group by MatchedID
  , Name
  , AddDate
  , Address
  , phoneNumber

SQL Fiddle with demo

这两个都会返回您的预期结果。

评论后修改：

您可以使用如下语句对相关行进行分组：

with NoDuplicates as
(
  select *
    , rownum = row_number() over (partition by MatchedID order by NewID)
  from Accounts
  where NewID <> MatchedID
)
select groupID = MatchedID
  , Acct = MatchedID
  , FirstName
  , AddDate
  , Address
  , phoneNumber
from NoDuplicates where rownum = 1
union all
select groupID = coalesce(am.MatchedID, a.NewID)
  , Acct = a.MatchedID
  , a.FirstName
  , a.AddDate
  , a.Address
  , a.phoneNumber
from Accounts a
  -- join to the corresponding matched account
  left join Accounts am on a.MatchedID = am.NewID and am.NewID <> am.MatchedID
where a.NewID = a.MatchedID
order by groupID, Acct

SQL Fiddle with demo

但是，这基本上只是按MatchedID分组。如果您希望编号组从1开始，则可以在语句中添加DENSE_RANK子句：

with NoDuplicates as
(
  select *
    , rownum = row_number() over (partition by MatchedID order by NewID)
  from Accounts
  where NewID <> MatchedID
)
, GroupedAcct as
(
  select GroupID = MatchedID
    , Acct = MatchedID
    , FirstName
    , AddDate
    , Address
    , phoneNumber
  from NoDuplicates where rownum = 1
  union all
  select GroupID = coalesce(am.MatchedID, a.NewID)
    , Acct = a.MatchedID
    , a.FirstName
    , a.AddDate
    , a.Address
    , a.phoneNumber
  from Accounts a
    -- join to the corresponding matched account
    left join Accounts am on a.MatchedID = am.NewID and am.NewID <> am.MatchedID
  where a.NewID = a.MatchedID
)
select GroupID = Dense_Rank() over (order by GroupID)
  , Acct
  , FirstName
  , AddDate
  , Address
  , phoneNumber
from GroupedAcct
order by groupID, Acct

SQL Fiddle with demo

SSRS组基于两列

1 个答案: