我想在文章的展示页面上展示相关文章。当用户查看任何特定文章时,db中的所有相关文章应该根据标记显示在该页面上(在右侧栏中)(因为每篇文章至少有一个标签)。我的应用程序有标签和文章之间的关系(请在下面)
articles_controller.rb
class ArticlesController < ApplicationController
before_filter :is_user_admin, only: [:new, :create, :edit, :destroy]
def is_user_admin
redirect_to(action: :index) unless current_user.try(:is_admin?)
return false
end
def index
@articles = Article.all(:order => "created_at DESC")
@article_titles = Article.first(10)
@tags = Tag.all
end
def show
@article = Article.find(params[:id])
end
def new
@article = Article.new
end
def create
@article = Article.new(params[:article])
@article.user_id = current_user.id
if @article.save
flash[:success] = "article created!"
redirect_to article_path(@article)
else
render 'new'
end
end
def destroy
@article = Article.find(params[:id])
@article.destroy
redirect_to action: 'index'
end
def edit
@article = Article.find(params[:id])
end
def update
@article = Article.find(params[:id])
if @article.update_attributes(params[:article])
flash.notice = "Article '#{@article.title}' Updated!"
redirect_to article_path(@article)
else
render 'edit'
end
end
end
tags_controller.rb
class TagsController < ApplicationController
#before_filter :user_signed_in, only: [:destroy]
def index
@tags = Tag.all
end
def show
@tag = Tag.find(params[:id])
end
end
schema.rb
ActiveRecord::Schema.define(:version => 20130411074056) do
create_table "articles", :force => true do |t|
t.string "title"
t.text "body"
t.datetime "created_at", :null => false
t.datetime "updated_at", :null => false
t.integer "user_id"
end
create_table "comments", :force => true do |t|
t.text "content"
t.integer "user_id"
t.string "article_id"
t.datetime "created_at", :null => false
t.datetime "updated_at", :null => false
end
create_table "taggings", :force => true do |t|
t.integer "tag_id"
t.integer "article_id"
t.datetime "created_at", :null => false
t.datetime "updated_at", :null => false
end
add_index "taggings", ["article_id"], :name => "index_taggings_on_article_id"
add_index "taggings", ["tag_id"], :name => "index_taggings_on_tag_id"
create_table "tags", :force => true do |t|
t.string "name"
t.datetime "created_at", :null => false
t.datetime "updated_at", :null => false
end
articles / show.html.erb: - 当用户根据标签查看任何特定文章时,我需要显示相关文章
目前articles / show.html.erb页面有标签(S)名称,我想显示db中具有相同标签的所有艺术品以显示在此页面上(右侧栏)。知道如何实现这种关系以获取相关文章以及在何处编写此逻辑以及如何在视图中实现。
答案 0 :(得分:7)
如果您使用acts_as_taggable_on,使用以下代码
可以轻松实现您想要的效果def show
@article = Article.find(params[:id])
@related_articles = Article.tagged_with(@article.tag_list, any: true)
end
由于您汇总了自己的实现,因此您必须手动执行提取。
首先获取文章所有标签的列表。那将是@article.tag_ids
。
接下来,获取与这些标记ID相关联的文章列表
@related_articles = Article
.joins(:taggings)
.where('articles.id != ?', @article.id)
.where(taggings: { tag_id: @article.tag_ids })