Question

我有两个表，我将其称为table1和table2。 Table1有2个字段，id和auth，table2也有两个字段，id和keywords。请注意，table1和table2的id匹配。这是我的问题：

SELECT id, MATCH(keywords) AGAINST('example') FROM table2 WHERE MATCH(keywords) AGAINST('example')

如何排除同一个id的auth（table1）不是1的结果？

Answer 1

SELECT id, MATCH(keywords) AGAINST('example') 
  FROM table2 t2
 WHERE MATCH(keywords) AGAINST('example')
   AND NOT EXISTS (select 1 from table1 t1 where t1.id = t2.id and t1.auth != 1)

Answer 2

  SELECT * 
  FROM table1 t1
  INNER JOIN table2 t2
  ON t1.id != t2.id

SQL连接结果全文

2 个答案: