Question

假设我有这段代码：

DECLARE @IncludeDuplicateAddressIDs tinyint

-- Value of @IncludeDuplicateAddressIDs set here ! --

IF(@IncludeDuplicateAddressIDs = 1)
     SELECT AddressIds FROM RTS.ADDRESSES
ELSE
     SELECT DISTINCT(AddressIds) FROM RTS.ADDRESSES

我可以将两个SELECT语句组合成一个吗？也就是说，只使用一个SELECT，我会显示所有的AddressID，或者只显示其中一个？

Answer 1

你可以这样做：

SELECT AddressIds FROM RTS.ADDRESSES WHERE @IncludeDuplicateAddressIDs = 1
UNION ALL
SELECT DISTINCT(AddressIds) FROM RTS.ADDRESSES WHERE @IncludeDuplicateAddressIDs <> 1

由于WHERE子句是互斥的，因此只有UNION个查询中的一个会返回一些行;另一个查询将不返回任何内容。

Answer 2

如果表包含唯一列，则可以使用此选项（假设唯一列的名称为Id）：

DECLARE @IncludeDuplicateAddressIDs tinyint = 1
SELECT AddressIds
FROM RTS.ADDRESSES
GROUP BY CASE WHEN @IncludeDuplicateAddressIDs = 1 
              THEN Id ELSE AddressIds END, AddressIds

SQLFiddle上的演示

Answer 3

您可以包含重复地址的数量。

SELECT AddressIDs, count(*) as cnt
FROM RTS.ADDRESSES
GROUP BY AdressIDs

Answer 4

您可以使用sp_executesql动态sql将查询形成为字符串（并根据需要设置多个列），然后执行它：

DECLARE @IncludeDuplicateAddressIDs tinyint
DECLARE @Columns varchar(500);  

IF(@IncludeDuplicateAddressIDs = 1) SET @Columns='AddressIds'
ELSE SET @Columns='DISTINCT(AddressIds)'

EXECUTE sp_executesql N'SELECT ' + @Columns +  'AddressIds FROM RTS.ADDRESSES';

Answer 5

试试这个 -

DECLARE @IncludeDuplicateAddressIDs TINYINT 
SELECT @IncludeDuplicateAddressIDs = 0

SELECT t.AddressIds
FROM (
    SELECT 
          AddressIds
        , cnt = ROW_NUMBER() OVER (PARTITION BY AddressIds ORDER BY AddressIds)
    FROM RTS.ADDRESSES
) t
WHERE @IncludeDuplicateAddressIDs = 1
    OR (@IncludeDuplicateAddressIDs != 1 AND cnt = 1)

在此查询中，未使用UNION或DISTINCT构造。因此，SQL可以生成更有效的查询计划。

根据另一个变量的值选择列？

5 个答案: