Question

我正在研究搜索功能，它在四天前工作正常，现在它正在返回此错误

您的SQL语法有错误;检查与MySQL服务器版本对应的手册，以便在第1行的'AND state ='AZ''附近使用正确的语法

这条线的正确语法是什么？

if($search_state !== "") {

$query .="AND state =  '" . $search_state .  " ' " ;

整个部分是：

$query = "SELECT id, name, contact, contact2, address1, address2, city, state, postalcode, country, location, workphone, fax, email, webaddress, region, rail, food, forest, metal, bulk, chem, general, paper FROM companies_new WHERE dummy = '' ORDER BY state ASC ";

if($search_co !== "") {

$query .= "AND name LIKE '%" . $search_co ."%' ";

}


if($search_first !== "") {

$query .= "AND contact LIKE '%" .$search_first."%' ";

}

if($search_last !== "") {

$query .= "AND contact LIKE '%" .$search_last."%' ";

}

if($search_city !== "") {

$query .="AND city = ' " . $search_city . " ' ";

}

if($search_state !== "") {

$query .="AND state =  '" . $search_state .  " ' " ;

}

Answer 1

AND之后，您无法为WHERE子句添加ORDER BY个连词。您的ORDER BY子句必须在完整的WHERE子句之后。

Answer 2

WHERE部分位于代码中的AND之前，这是错误的。这就是你想要的

$query = "SELECT id, name, contact, contact2, address1, address2, city, state, postalcode, country, location, workphone, fax, email, webaddress, region, rail, food, forest, metal, bulk, chem, general, paper FROM companies_new WHERE dummy = '' ";

if($search_co !== "") {

$query .= "AND name LIKE '%" . $search_co ."%' ";

}
...
$query .= " ORDER BY state ASC ";

另外，为了完整起见，您可以使代码更容易阅读：

$query .= "AND name LIKE '%$search_co%' ";

因为你的字符串是双引号

Answer 3

您需要将AND语句放在where之后和sort_by之前。将sort_by移动到php的末尾（附加到查询字符串），它应该可以工作。

Answer 4

试试这个：

$query = "SELECT id, name, contact, contact2, address1, address2, city, state, postalcode, country, location, workphone, fax, email, webaddress, region, rail, food, forest, metal, bulk, chem, general, paper FROM companies_new WHERE dummy = '' ";  

if($search_co !== "") {
    $query .= "AND name LIKE '%".$search_co."%' ";
}

if($search_first !== "") {
    $query .= "AND contact LIKE '%".$search_first."%' ";
}

if($search_last !== "") {
    $query .= "AND contact LIKE '%".$search_last."%' ";
}

if($search_city !== "") {
    $query .= "AND city = '".$search_city."' ";
}

if($search_state !== "") {
    $query .= "AND state = '". $search_state."' " ;
}

$query.= "ORDER BY state ASC"

正如其他人所说，你的order by声明必须是最后的。此外，您在查询的city =部分中有城市名称周围的空格。虽然这是有效的SQL语法，但它只会返回城市名称被空格包围的结果。我猜这不是你想要的。

此外，您可能还想在order by中添加更多字段。现在，它将由州订购，但记录将由州随机回来。也许像是

$query.= "ORDER BY state, city, name, id"

最后，仅供参考，如果您没有仔细清理搜索输入，这种方法很容易受到SQL注入的影响。

Answer 5

我认为这可行：

$query = "SELECT id, name, contact, contact2, address1, address2, city, state, postalcode, country, location, workphone, fax, email, webaddress, region, rail, food, forest, metal, bulk, chem, general, paper FROM companies_new ";

$conditions = array();

if(!empty($search_co)) {
    $conditions[] = "name LIKE '%" . $search_co ."%' ";
}

if(!empty($search_first)) {
    $conditions[] = "contact LIKE '%" .$search_first."%' ";
}

if(!empty($search_last)) {
    $conditions[] = "contact LIKE '%" .$search_last."%' ";
}

if(!empty($search_city)) {
    $conditions[] = "city = '" . $search_city . "' ";
}

if(!empty($search_state)) {
    $conditions[] = "state =  '" . $search_state .  "' " ;
}

if (count($conditions) > 0) {
    $query .= " WHERE " . implode(' AND ', $conditions);
}

$query .= " ORDER BY state ASC";

编辑：原始版本使用空，应该是！空的。现在已经修好了。

编辑2：这也假设您已使用mysql_real_escape_string或类似内容对变量进行了清理。

请注意，ORDER BY必须位于WHERE子句之后。

implode接受一个数组并将其转换为一个字符串，其中包含元素之间的指定字符串。所以，给定：

$myArray = array('A', 'B', 'C');

你可以做到

$myString = implode(' and ', $myArray);

将“A和B和C”放入$myString。

Answer 6

此外，您似乎在单引号和双引号之间有空格，这将使查询如下所示：AND state ='AZ'，这可能不是您想要的。您还可以使用以下语法避免PHP中的其他引号和连接：

$query .= " AND state = '$search_state' ";

当然，我必须提到您应该清理输入以防止SQL注入。

Php语法帮助

6 个答案: