在Eloquent中有许多与分类法的关系

时间:2013-04-17 16:06:35

标签: php laravel relationship laravel-4 eloquent

我正在使用Laravel 4.我的系统中有很多关系。我选择使用Wordpress分类表方案。

但是如何与Laravel 4 Eloquent ORM建立模型关系?这是我的数据库表;

terms

+------------+---------------------+------+-----+---------+----------------+
| Field      | Type                | Null | Key | Default | Extra          |
+------------+---------------------+------+-----+---------+----------------+
| term_id    | bigint(20) unsigned | NO   | PRI | NULL    | auto_increment |
| name       | varchar(200)        | NO   | MUL |         |                |
| slug       | varchar(200)        | NO   | UNI |         |                |
+------------+---------------------+------+-----+---------+----------------+

term_taxonomy

+------------------+---------------------+------+-----+---------+----------------+
| Field            | Type                | Null | Key | Default | Extra          |
+------------------+---------------------+------+-----+---------+----------------+
| term_taxonomy_id | bigint(20) unsigned | NO   | PRI | NULL    | auto_increment |
| term_id          | bigint(20) unsigned | NO   | MUL | 0       |                |
| taxonomy         | varchar(32)         | NO   | MUL |         |                |
| description      | longtext            | NO   |     | NULL    |                |
| parent           | bigint(20) unsigned | NO   |     | 0       |                |
| count            | bigint(20)          | NO   |     | 0       |                |
+------------------+---------------------+------+-----+---------+----------------+

term_relationships

+------------------+---------------------+------+-----+---------+-------+
| Field            | Type                | Null | Key | Default | Extra |
+------------------+---------------------+------+-----+---------+-------+
| object_id        | bigint(20) unsigned | NO   | PRI | 0       |       |
| term_taxonomy_id | bigint(20) unsigned | NO   | PRI | 0       |       |
| term_order       | int(11)             | NO   |     | 0       |       |
+------------------+---------------------+------+-----+---------+-------+

通常情况下,我们可以return $this->belongsToMany('Term');,但我们怎样才能做到2个关系?在找到与“taxonomy_id”的术语关系之后,我们需要2个关系首先从“term_taxonomy”表中找到术语分类。

我想要如何使用的一个例子;

$categories = Post::find(1)->categories; // get terms with taxonomy="post_category" 
$tags = Post::find(1)->tags; // get terms with taxonomy="post_tag" 

我不想用基本的数据库类“DB::table('table')->join('...')...”做这个。我想使用Eloquent关系方法和模型。

1 个答案:

答案 0 :(得分:2)

您可以创建getter方法来处理这些:

在Post模型中,按照以下方式创建新方法:

public function getCategories()
{
    return $this->hasMany()->where('taxonomy', 'post_category');
}

public function getTags()
{
    return $this->hasMany()->where('taxonomy', 'post_tag');
}