我正在尝试为类创建映射:
public class Employer
{
public virtual int Id { get; protected set; }
public virtual string Name { get; set; }
public virtual IList<Field> Fields { get; set; }
public virtual string Location { get; set; }
public virtual string Phone { get; set; }
}
public class Field
{
public virtual int Id { get; protected set; }
public virtual string Description { get; set; }
}
我的映射看起来像:
<hibernate-mapping xmlns="urn:nhibernate-mapping-2.2" namespace="lab" assembly="lab">
<class name="Employer" table="Employer">
<id name="Id">
<generator class="native"/>
</id>
<property name="Name" />
<list name="Fields" cascade="all-delete-orphan">
<key column="EmployerId" />
<index column="FieldIndex" />
<one-to-many class="Field"/>
</list>
<property name="Location" />
<property name="Phone" />
</class>
</hibernate-mapping>
<hibernate-mapping xmlns="urn:nhibernate-mapping-2.2" namespace="lab" assembly="lab">
<class name="Field" table="Field">
<id name="Id">
<generator class="native"/>
</id>
<property name="Description" />
</class>
</hibernate-mapping>
代码如下:
var session = configuration.BuildSessionFactory().OpenSession();
var transaction = session.BeginTransaction();
var emp = new Employer();
emp.Name = "Mera";
emp.Fields = new List<Field> ();
emp.Fields.Add(new Field() { Description = "C#" });
emp.Fields.Add(new Field() { Description = "C++" });
emp.Location = "Street";
emp.Phone = "02";
session.Save(emp);
transaction.Commit();
var transaction2 = session.BeginTransaction();
var emp2 = new Employer();
emp2.Name = "Mera2";
emp2.Fields = session.CreateQuery("from Field").List<Field>();
emp2.Location = "Street";
emp2.Phone = "02";
session.Save(emp2);
transaction2.Commit();
此代码只是将Field表中的旧条目替换为第二个雇主的新条目。因此,Field表仍有2条记录,Employer表有2条记录。
你可以理解我需要,如果2个字段相同(相同的描述),2个雇主都应该有相同的对象引用。
答案 0 :(得分:3)
正如JamesB在评论中所说,这看起来像是多对多的关系。多对多关系需要一个中间表,否则你将获得你所看到的行为。
要获得所需的行为,您需要创建一个名为EmployerFields
的新表。此表需要有两个外键字段,一个用于Employer
,另一个用于Fields
,还有一个字段用于索引FieldIndex
。 FK可以分别称为EmployerId
和FieldId
。
然后需要更改列表映射,如下所示。
<list name="Fields" cascade="all-delete-orphan" table="EmployerFields">
<key column="EmployerId" />
<index column="FieldIndex" />
<many-to-many class="Field" column="FieldId" />
</list>