Question

我正在ASP.NET MVC中构建一个应用程序（使用C＃），我想知道如何在我的控制器中执行curl http://www.mywebsite.com/clients_list.xml之类的调用基本上我想构建一种REST API来执行诸如show edit和delete之类的操作，比如Twitter API。

但不幸的是，到目前为止，我在本网站上找不到除了cURL for windows之外的任何内容：http://curl.haxx.se/

所以我不知道是否有任何传统的方式从URL中检索这种类型的调用方法，例如删除帖子和放置请求等等......

我只是想知道一种简单的方法来在我的ASP.NET MVC应用程序中执行控制器内的curl等命令。

更新：

嗨所以我设法做了GET请求，但现在我在检索POST请求时遇到了严重的问题，例如，我正在使用来自Twitter的更新状态API，curl会像这样工作：

curl -u user:password -d "status=playing with cURL and the Twitter API" http://twitter.com/statuses/update.xml

但是在我的ASP.NET MVC应用程序中，我在我的自定义函数中这样做：

string responseText = String.Empty;
HttpWebRequest request = (HttpWebRequest)WebRequest.Create("http://twitter.com/statuses/update.xml");
request.Method = "POST";
request.Credentials = new NetworkCredential("username", "password");
request.Headers.Add("status", "Tweeting from ASP.NET MVC C#");
HttpWebResponse response = (HttpWebResponse)request.GetResponse();
using (StreamReader sr = new StreamReader(response.GetResponseStream()))
{
    responseText = sr.ReadToEnd();
}
return responseText;

现在的问题是这个请求正在返回403 Forbidden，我真的不知道为什么它在curl上完美运作

：\

更新：

我终于设法让它工作了，但是可能有一种方法可以使它更清洁和漂亮，因为我是C＃的新手我需要更多的知识去做，POST params传递的方式让我非常困惑因为很多代码只能传递params。

好吧，我已经创建了一个Gist - http://gist.github.com/215900，所以每个人都可以随意修改它。感谢您的帮助çağdaş

也请遵循以下代码：

public string TwitterCurl()
{
    //PREVENT RESPONSE 417 - EXPECTATION FAILED
    System.Net.ServicePointManager.Expect100Continue = false;

    HttpWebRequest request = (HttpWebRequest)WebRequest.Create("http://twitter.com/statuses/update.xml");
    request.Method = "POST";
    request.Credentials = new NetworkCredential("twitterUsername", "twitterPassword");

    //DECLARE POST PARAMS
    string headerVars = String.Format("status={0}", "Tweeting from ASP.NET MVC C#");
    request.ContentLength = headerVars.Length;

    //SEND INFORMATION
    using (StreamWriter streamWriter = new StreamWriter(request.GetRequestStream(), ASCIIEncoding.ASCII))
    {
        streamWriter.Write(headerVars);
        streamWriter.Close();
    }

    //RETRIEVE RESPONSE
    string responseText = String.Empty;
    using (StreamReader sr = new StreamReader(request.GetResponse().GetResponseStream()))
    {
        responseText = sr.ReadToEnd();
    }

    return responseText;

    /*
    //I'M NOT SURE WHAT THIS IS FOR            
        request.Timeout = 500000;
        request.ContentType = "application/x-www-form-urlencoded";
        request.UserAgent = "Custom Twitter Agent";
        #if USE_PROXY
            request.Proxy = new WebProxy("http://localhost:3000", false);
        #endif
    */
}

Answer 1

尝试使用Microsoft.Http.HttpClient。这是您的请求的样子

var client = new HttpClient();
client.DefaultHeaders.Authorization = Credential.CreateBasic("username","password");

var form = new HttpUrlEncodedForm();
form.Add("status","Test tweet using Microsoft.Http.HttpClient");
var content = form.CreateHttpContent();

var resp = client.Post("http://www.twitter.com/statuses/update.xml", content);
string result = resp.Content.ReadAsString();

您可以在WCF REST Starter kit Preview 2中找到此库及其来源，但它可以独立于其中的其他内容使用。

P.S。我在我的推特账户上测试了这段代码，但它确实有用。

Answer 2

使用HttpWebRequest和HttpWebResponse的示例代码：

public string GetResponseText(string url) {
    string responseText = String.Empty;
    HttpWebRequest request = (HttpWebRequest)WebRequest.Create(url);
    request.Method = "GET";
    HttpWebResponse response = (HttpWebResponse)request.GetResponse();
    using (StreamReader sr = new StreamReader(response.GetResponseStream())) {
        responseText = sr.ReadToEnd();
    }
    return responseText;
}

要发布数据：

public string GetResponseText(string url, string postData) {
    string responseText = String.Empty;
    HttpWebRequest request = (HttpWebRequest)WebRequest.Create(url);
    request.Method = "POST";
    request.ContentLength = postData.Length;
    using (StreamWriter sw = new StreamWriter(request.GetRequestStream())) {
        sw.Write(postData);
    }
    HttpWebResponse response = (HttpWebResponse)request.GetResponse();
    using (StreamReader sr = new StreamReader(response.GetResponseStream())) {
        responseText = sr.ReadToEnd();
    }
    return responseText;
}

Answer 3

这是我用于调用返回JSON的RESTful API的单行代码。

return ((dynamic) JsonConvert.DeserializeObject<ExpandoObject>(
        new WebClient().DownloadString(
            GetUri(surveyId))
    )).data;

备注

使用surveyId和凭据
在舞台上生成Uri
'data'属性是返回的反序列化JSON对象的一部分通过SurveyGizmo API

完整服务

public static class SurveyGizmoService { public static string UserName { get { return WebConfigurationManager.AppSettings["SurveyGizmo.UserName"]; } } public static string Password { get { return WebConfigurationManager.AppSettings["SurveyGizmo.Password"]; } } public static string ApiUri { get { return WebConfigurationManager.AppSettings["SurveyGizmo.ApiUri"]; } } public static string SurveyId { get { return WebConfigurationManager.AppSettings["SurveyGizmo.Survey"]; } } public static dynamic GetSurvey(string surveyId = null) { return ((dynamic) JsonConvert.DeserializeObject<ExpandoObject>( new WebClient().DownloadString( GetUri(surveyId)) )).data; } private static Uri GetUri(string surveyId = null) { if (surveyId == null) surveyId = SurveyId; return new UriBuilder(ApiUri) { Path = "/head/survey/" + surveyId, Query = String.Format("user:pass={0}:{1}", UserName, Password) }.Uri; } }

Answer 4

查看System.Net。WebClient类。它应该提供您需要的功能。对于更精细的控制，您可能会发现WebRequest更有用，但WebClient似乎最适合您的需求。

ASP.NET MVC - 使用cURL或类似方法在应用程序中执行请求

4 个答案: