我有一个名为transaction_detail的表，其中包含id_transd，id_trans，id_cust和inputtime。
id_transd | id_trans | id_cust | inputtime |
1 | 1 | 1 | 2013-04-15 16:55:58 |
2 | 1 | 1 | 2013-05-15 16:55:58 |
3 | 1 | 1 | 2013-06-15 16:55:58 |
4 | 2 | 2 | 2013-06-15 16:55:58 |
...
我想得到具有相同id_cust和id_trans的输入时间量。
例如：当admin想要计算一个客户的工作完成时间，然后管理员需要点击该名称的客户和系统将计算日期。
|No.| Name | Process | Time |
|1. | D-net | by sales | 2013-04-15 16:55:58 |
| | | by sadmin | 2013-05-15 16:55:58 |
| | | by technic | 2013-06-15 16:55:58 |
我试过这段代码
SELECT t.* datediff(DAY, t.inputtime, nextdate) AS Days_Between
FROM
(SELECT t.*,
(SELECT min(inputtime)
FROM transaksi_detail t2
WHERE t.id_cust = t2.id_cust
AND t.id_trans = t2.id_trans
AND t.inputtime < t2.inputtime) AS nextdate
FROM transaction_detail t)t
但是不行，它说：
Warning: mysql_fetch_array() expects parameter 1 to be resource, boolean given in F:\htdocs\indosat2\hitung_tanggal2.php on line 20