Question

我正在尝试编写一个程序来计算并显示高于60英寸的学生的身高。例如：我需要它来计算和显示高于60英寸的学生数量并显示各自的高度。我不确定如何存储单独的值并显示它们的高度。我已经得到了计算高于60英寸的学生数量的计划，但我需要帮助显示他们的特定身高。

#include <iostream>

using namespace std;

int main()
{
    double count60 = 0.0;
    double height[10];
    for (int x = 0; x < 10; x = x + 1)
    {
        height[x] = 0.0;
    }

    cout << "You are asked to enter heights of 10 students. "<< endl;
    for (int x = 0; x < 10; x = x + 1)
    {
        cout << "Enter height of a student: ";
        cin >> height[x];
    if (height[x] > 60)
    {
        count60 = count60 + 1;
    }       
    }

    cout << "The number of students taller than 60 inches: "<< count60 << endl;
    cout << "The heights of these students are: "

    system("pause"); 
    return 0;
}

Answer 1

不确定我完全明白你的问题所在。

从您提供的代码中可以清楚地知道如何：

遍历数组（您的for语句输入）;
判断某事是否大于60（您的if语句更新计数）;和
输出一个变量（倒数第二个cout <<声明。

因此将这些与以下内容结合起来应该是一件简单的事情：

for (int x = 0; x < 10; x = x + 1) {
    if (height[x] > 60) {
        cout << height << '\n';
    }
}

Answer 2

以下是代码：

#include <iostream>

using namespace std;

int main()
{
double count60 = 0.0;
double height[10];
for (int x = 0; x < 10; x = x + 1)
{
    height[x] = 0.0;
}

cout << "You are asked to enter heights of 10 students. "<< endl;
for (int x = 0; x < 10; x = x + 1)
{
    cout << "Enter height of a student: ";
    cin >> height[x];
if (height[x] > 60)
{
    count60 = count60 + 1;
}       
}

cout << "The number of students taller than 60 inches: "<< count60 << endl;
cout << "The heights of these students are: ";
for(int i=0;i<10;++i)
    if(height[i]>60)
        cout<<' '<<height[i];
cout<<endl;

return 0;

}

顺便说一句，我认为count60最好是unsigned int。

Answer 3

尝试使用std::vector。它们基本上是数组的包装器，允许您动态添加值。在这种情况下，您将添加代码：

#include <vector> // obviously with the rest of the includes.

std::vector<int> tallPeople;
for (int x = 0; x < 10; x = x + 1)
{
    if (height[x] > 60)
    {
        count60 = count60 + 1;
        tallPeople.push_back(height[x]);
    }   
}

//...

for (int num = 0; num < tallPeople.size(); num++)
{
    cout << tallPeople[num] << endl;
}

Answer 4

在这里你......在空间利用方面不是最好但是避免了STL。

        #include <iostream>

        using namespace std;

        int main()
        {
            int count60 = 0;
            double height[10];
            double maxheight[10];
            for (int x = 0; x < 10; x = x + 1)
            {
                height[x] = 0.0;
            }

            cout << "You are asked to enter heights of 10 students. "<< endl;
            for (int x = 0; x < 10; x = x + 1)
            {
                cout << "Enter height of a student: ";
                cin >> height[x];
            if (height[x] > 60)
            {
                maxheight[count60] = height[x];
                count60 = count60 + 1;
            }       
            }

            cout << "The number of students taller than 60 inches: "<< count60 << endl;

            for (int i = 0; i < count60; i = i + 1)
            {
               cout<<"The heights of these students are: "<< maxheight[i] << endl;
            }

            system("pause"); 
            return 0;
        }

Answer 5

如果您想删除重复项，请执行此操作

//bubble sort
for(int i=0;i<9;i++)
{
    for(int j=i+1;j<10;j++)
    {
        if(height[i]>height[j])
        {
            double temp = height[i];
            height[i] = height[j];
            height[j] = temp;
        }       
    }
}   
//print
for(int i=0;i<10;i++)
{
    if(height[i]>60 && (i==0 || height[i]!= height[i-1]))   
    {
        cout << ' ' << height[i];
    }   
}

需要帮助在循环/数组程序C ++中显示值

5 个答案: