Question

晚安！

我有一个名为SWIMMER的表，需要找到（在名为TIME的NUMERIC字段中）给定时间间隔内某些值的ocorrence数（我使用的是Oracle10g）。我需要展示类似的东西：

23更高或相等TIME显示HorizontalBar值为300
22,3更高或相等TIME次要或相等23显示HorizontalBar值140
21,6更高或相等TIME次要或等于22,3显示HorizontalBar值为15
20,9更高或相等TIME次要或相等21,6显示HorizontalBar值3

可能有一个查询有这样的返回？我怎么能组装该查询？（注意：次要或相等是符号，我不能在这里发帖，因为它每次都会出错）

最诚挚的问候，

Answer 1

尝试这样的事情（Here is a sqlfiddle）：

select case 
           when time >= 23 then '23 =< TIME'
           when time < 23 and time >= 22.3 then '23 > TIME >= 22,3'
           when time < 22.3 and time >= 21.6 then '22,3 > TIME >= 21,6'
           when time < 21.6 and time >= 20.9 then '21,6 > TIME >= 20,9'
           else '20,9 > TIME'
        end   || ' with value '|| count(*) v
from your_table
group by case 
           when time >= 23 then '23 =< TIME'
           when time < 23 and time >= 22.3 then '23 > TIME >= 22,3'
           when time < 22.3 and time >= 21.6 then '22,3 > TIME >= 21,6'
           when time < 21.6 and time >= 20.9 then '21,6 > TIME >= 20,9'
           else '20,9 > TIME'
         end

和结果：

21,6 > TIME >= 20,9 with value 8 
20,9 > TIME with value 4 
22,3 > TIME >= 21,6 with value 6 
23 > TIME >= 22,3 with value 15 
23 =< TIME with value 66

更新：正如DavidAldrige建议你可以有一个子查询：

select intrvl || ' with value '|| count(*) v
from
(select case 
           when time >= 23 then '23 =< TIME'
           when time < 23 and time >= 22.3 then '23 > TIME >= 22,3'
           when time < 22.3 and time >= 21.6 then '22,3 > TIME >= 21,6'
           when time < 21.6 and time >= 20.9 then '21,6 > TIME >= 20,9'
           else '20,9 > TIME'
        end   intrvl, time
from t)
group by intrvl

And here is another demo

JFreeChart使用数字查询ORACLE

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