Question

我有一个包含2列EmployeeId（int）和EmployeeDetails（XMl类型）的表

EmployeeId EmployeeDetails

1＆lt; Employee＆gt;＆lt; EmployeeDetails＆gt;＆lt; EmployeeName＆gt; Priyanka＆lt; / EmployeeName＆gt;＆lt; Age＆gt; 24＆lt; / Age＆gt;＆lt;地址＆gt;阿根廷＆LT; /地址＆gt;＆LT; / EmployeeDetails＆GT;＆LT; /雇员＆GT;

2＆lt; Employee＆gt;＆lt; EmployeeDetails＆gt;＆lt; EmployeeName＆gt; Sarkar＆lt; / EmployeeName＆gt;＆lt; Age＆gt; 28＆lt; / Age＆gt;＆lt;地址＆gt;澳大利亚和LT; /地址＆gt;＆LT; / EmployeeDetails＆GT;＆LT; /雇员＆GT;

我需要输出

EmployeeId EmpName年龄地址

1 Priyanka 24 Argentina

2 Sarkar 28 Australia

请帮助我，因为我是xml的新手

Answer 1

联机丛书在XML方面有点难以理解;您可以尝试使用此网站寻求帮助：http://blogs.msdn.com/mrorke/archive/2005/06/01/423965.aspx这里有一段代码可以帮助您。

DECLARE @Employees TABLE
    (
      EmployeeID INT ,
      EmployeeDetails XML
    )

INSERT  INTO @Employees
        ( EmployeeID ,
          EmployeeDetails 
        )
VALUES  ( 1 ,
          '<Employee><EmployeeDetails><EmployeeName> Priyanka </EmployeeName><Age> 24 </Age><Address> Argentina</Address></EmployeeDetails></Employee>'

        )


INSERT  INTO @Employees
        ( EmployeeID ,
          EmployeeDetails 
        )
VALUES  ( 2 ,
          '<Employee><EmployeeDetails><EmployeeName> Sarkar </EmployeeName><Age> 28 </Age><Address> Australia</Address></EmployeeDetails></Employee>'
        )


SELECT  EmployeeID ,
        EmployeeName = m.value('EmployeeName[1]', 'varchar(50)') ,
        Age = m.value('Age[1]', 'int') ,
        Address = m.value('Address[1]', 'varchar(100)')
FROM    @Employees e
        CROSS APPLY EmployeeDetails.nodes('/Employee/EmployeeDetails') AS e1 ( m )

处理XML数据类型（SQL SERVER 2005）

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