Question

我希望在两个sql查询之间建立连接，在“WHERE”子句中的两个不同列中显示相同的字段，如以下示例所示：

查询n°1：

SELECT  COUNT([ID]) AS SOCIETE_1,
        CAST([Créé le] AS date) AS DateCreated
FROM [MFilesCloudReport].[dbo].[Document]
WHERE [Société_ID] = 1
GROUP BY CAST([Créé le] AS date)
ORDER BY CAST([Créé le] AS date)

- ＆GT; 结果n°1：

SOCIETE_1   DateCreated
-----------------------------------
142     |   2013-01-17
148     |   2013-01-21
88      |   2013-01-23
188     |   2013-01-25
187     |   2013-01-29
124     |   2013-01-31

查询n°2：

SELECT  COUNT([ID]) AS SOCIETE_2,
    CAST([Créé le] AS date) AS DateCreated
FROM [MFilesCloudReport].[dbo].[Document]
WHERE [Société_ID] = 2
GROUP BY CAST([Créé le] AS date)
ORDER BY CAST([Créé le] AS date)

- ＆GT; 结果n°2：

SOCIETE_2   DateCreated
-----------------------------------
18      |   2013-01-17
73      |   2013-01-21
75      |   2013-01-23
1       |   2013-01-24
48      |   2013-01-25
80      |   2013-01-29
43      |   2013-01-31

预期结果将是这一个：

SOCIETE_1     SOCIETE_2     TOTAL       DateCreated
----------------------------------------------------------------------------
142         |   18      |   160     |   2013-01-17
148         |   73      |   221     |   2013-01-21
88          |   75      |   163     |   2013-01-23
0           |   1       |   1       |   2013-01-24
188         |   48      |   236     |   2013-01-25
187         |   80      |   267     |   2013-01-29
124         |   43      |   167     |   2013-01-31

提前感谢您的帮助和美好的一天。

Answer 1

SELECT  COUNT(case when [Société_ID] = 1 then [ID] end) AS SOCIETE_1,
        COUNT(case when [Société_ID] = 2 then [ID] end) AS SOCIETE_2,
        COUNT(*) AS TOTAL,
        CAST([Créé le] AS date) AS DateCreated
FROM [MFilesCloudReport].[dbo].[Document]
GROUP BY CAST([Créé le] AS date)
ORDER BY CAST([Créé le] AS date)

concat sql query＆gt;根据where子句在2个不同的列中显示相同的列

1 个答案: