实现线程作业超时的最常见做法是什么(即:在最多X秒后终止作业)?
我写了以下python代码。我读了很多不同的方法来实现这个,但我有点迷失......我是否必须用计时器做这个?或者通过计算add_timeout
回调?
作为旁注,thread.join(timeout)
的使用在gtk / threaded应用程序中非常有限,因为它阻止了主线程?
谢谢!
注意:我对python / threading
很新#!/usr/bin/python
import time
import threading
import gobject
import gtk
import glib
gobject.threads_init()
class myui():
def __init__(self):
interface = gtk.Builder()
interface.add_from_file("myui.glade")
interface.connect_signals(self)
self.spinner = interface.get_object('spinner1')
def bg_work1(self):
print "work has started"
# simulates some work
time.sleep(5)
print "work has finished"
def startup(self):
thread = threading.Thread(target=self.bg_work1)
thread.start()
# work started. Now while the work is being done I want
# a spinner to rotate
self.spinner.start()
print "spinner started"
#thread.join() # I wanna wait for the job to be finished while the spinner spins.
# but this seems to block the main thread, and so the gui doesn't shows up !
glib.timeout_add(100, self.check_job, thread, 5)
def check_job(self, thread, timeout):
#print 'check job called'
if not thread.isAlive():
print 'is not alive anymore'
self.spinner.stop()
return False
return True
if __name__ == "__main__":
app = myui()
app.startup()
print "gtk main loop starting !"
gtk.main()
print "gtk main loop has stopped !"
答案 0 :(得分:0)
您的代码似乎相当不错,唯一缺少的是使用和评估超时点:
glib.timeout_add(100, self.check_job, thread, time.time() + 5)
def check_job(self, thread, timeout):
#print 'check job called'
if not thread.isAlive():
print 'is not alive anymore'
self.spinner.stop()
return False
if time.time() > timeout:
print 'job timed out'
self.spinner.stop()
return False
return True
但是,这不会在超时后终止您的工作线程,因此它仍将继续运行。我不知道强行终止Python线程的方法。您必须拆分工作并检查工作线程中的超时,以便它可以正常终止。