Question

我是一个完全的初学者;我刚刚开始编码，我遇到了这个问题。代码类型的工作除了它不会添加，减去，除法或其他任何东西：它只是说TypeError: unsupported operand type(s) for -: 'str' and 'str'或它只是把数字。有人能帮我吗？以下是代码示例：

a = input("Enter First Name:")
b = input("Enter Last Name:")
c = (" Welcome to the New World Order")
print ("Hey " + a + b+ c)
d = (": ")
num = input("Please enter a number "+a+b+d)
num1 = input("Please enter another number "+a+b+d)
num2 = num+num1
print ('is this your number umm ... ', (num2))
input ("Press<enter>")

Answer 1

输入始终是“str”（字符串）类型，您需要将它们转换为int或float以对它们进行数学运算。

num = int(input("Please enter a number "+a+b+d))

请注意，如果用户输入的内容不是有效数字，整个程序将崩溃，以处理您必须使用尝试，除。

Answer 2

fname = raw_input("Enter First Name:")
lname = raw_input("Enter Last Name:")
c = (" Welcome to the New World Order")
print ("Hey " + fname + " " + lname + c)
d = (": ")

num  = raw_input("Please enter a number "+ fname + " " + lname +" " + d)
num1 = raw_input("Please enter another Number "+ fname + " " + lname +" " + d)

num2 = int(num) +  int(num1)

print '%s %s is these your numbers umm ... '% (num,num1)
print '%d is sum of  your numbers umm ... '% (num2)
raw_input ("Press<enter>")

我认为这就是你想要做的。

如果你是新手，你应该先学习python。

使用此Learn Python the Hard Way

或更多概念Read Python Documentation

Answer 3

input()返回字符串，除非您先将它们转换为数字，否则会将它们连接起来而不是求和（并且在尝试减去，乘以或除以时会抛出TypeError它们）：

>>> "1" + "2"
'12'
>>> "1" - "2"
Traceback: <snip>
TypeError: unsupported operand type(s) for -: 'str' and 'str'
>>> "1" * "2"
Traceback: <snip>
TypeError: can't multiply sequence by non-int of type 'str'
>>> "1" * 2  # This is possible (but is still concatenation)!
'11'
>>> "1" / "2"
Traceback: <snip>
TypeError: unsupported operand type(s) for /: 'str' and 'str'

您需要使用int()：

从您的值创建整数

num2 = int(num) + int(num1)

如果ValueError或num不包含任何可以解释为整数的内容，则会抛出num1，因此您可能想要抓住它：

try:
    num2 = int(num) + int(num1)
    print ('is this your number umm ... ', num2)
except ValueError:
    print('You really should enter numbers!')

新手Python用户数学

3 个答案: