Question

我想选择一名员工并将他/她的薪水增加9.5％并保存数据库中的更改

查询如下。我在SQL Server 2008中使用了两个相关的表Employee_Tbl和Job_Tbl

SELECT  Employee_Tbl.EmployeeID, 
        Employee_Tbl.Salary,(Employee_Tbl.Salary*5/100)+Employee_Tbl.Salary as       
        SalaryIncreaseByFivePercent
FROM    Employee_Tbl INNER JOIN
                         Job_Tbl ON Employee_Tbl.JobTitle = Job_Tbl.JobTitle

我遇到了使用相同查询在数据库中保存其他列SalaryIncreaseByFivePercent的问题。任何人都能说出来吗？

Answer 1

您想在此处使用UPDATE声明。像下面这样的东西可以解决这个问题

UPDATE Emplotee_Tbl 
SET Employee_Tbl.Salary = (Employee_Tbl.Salary*5/100) + Employee_Tbl.Salary 
FROM Employee_Tbl AS et 
    INNER JOIN Job_Tbl AS jt 
        ON et.JobTitle = jt.JobTitle 
WHERE Employee_Tbl.EmployeeLastName = "Burns";
GO

我希望这会有所帮助。

编辑。要创建一个名为SalaryIncreaseByFivePercent的新列并在其中插入更新的工资，您只需使用

创建新列

ALTER TABLE table_name
ADD column_name datatype;
GO

Answer 2

我无法在选择查询中添加列

首先添加一个新列来存储float数据类型的增加的工资increasedSalary。

ALTER TABLE Employee_Tbl
ADD increasedSalary float

然后更新表

UPDATE Emplotee_Tbl 
SET increasedSalary = (Employee_Tbl.Salary*5/100) + Employee_Tbl.Salary
FROM Employee_Tbl  t 
   INNER JOIN Job_Tbl  j 
ON t.JobTitle = j.JobTitle

查询增加工资并保存在数据库中

2 个答案: