Question

我正在尝试使用查询值。

请看这段代码：

//Anything goes here
........
$show="SELECT *FROM persons";
$result=mysqli_query($con,$show);
echo "<form method='post'>";
echo "<table border=1>";
echo "<tr>";
echo "<td>name</td><td>Firstname</td><td>Lastname</td><td>address</td><td>phone</td>";
echo "</tr>";
while ($row=mysqli_fetch_array($result))
{
echo "<tr>";
echo "<td><input type='text' name='mname' value=".$row[0]."></td>";
echo "<td>".$row[1]."</td>";
echo "<td>".$row[2]."</td>";
echo "<td>".$row[3]."</td>";
echo "<td>".$row[4]."</td>";
echo "<td><input type='submit' name='single' value='edit'></td>";
echo "</tr>";
}
echo "</table>";
echo "</form>";
?>
<?
if (isset($_POST['single']))
{
$show="SELECT *FROM persons WHERE name='$_POST[mname]'";
//another sql query here
............
.............

但是，这不是正确的编码。我只想要用户点击编辑，然后它将为每个查询执行特定命令。但是在这里，循环之后它只会得到最后一行的$row[0]。如何执行此操作：当用户单击每行旁边的edit按钮时，它将只获得此行的值

Answer 1

试试我的代码。 page.php是您当前的页面

........
$show="SELECT *FROM persons";
$result=mysqli_query($con,$show);
echo "<form method='post'>";
echo "<table border=1>";
echo "<tr>";
echo "<td>name</td><td>Firstname</td><td>Lastname</td><td>address</td><td>phone</td>";
echo "</tr>";
while ($row=mysqli_fetch_array($result))
{
echo "<tr>";
echo "<td><input type='text' name='mname' value=".$row[0]."></td>";
echo "<td>".$row[1]."</td>";
echo "<td>".$row[2]."</td>";
echo "<td>".$row[3]."</td>";
echo "<td>".$row[4]."</td>";
echo "<td><a href='page.php?single=".$row[0]."'>edit</a></td>";
echo "</tr>";
}
echo "</table>";
echo "</form>";
?>
<?
if (isset($_GET['single']))
{
$show="SELECT *FROM persons WHERE name='$_GET[single]'";

Answer 2

如果出现以下其他情况，请保留您的代码：

// if form submitted then show edit form with selected person data
if (isset($_POST['single'])) {
    $show = "SELECT *FROM persons WHERE name='$_POST[mname]'";
//another sql query here
    ............
    .............
} else {
    $show = "SELECT *FROM persons";
    $result = mysqli_query($con, $show);

    echo "<table border=1>";
    echo "<tr>";
    echo "<td>name</td><td>Firstname</td><td>Lastname</td><td>address</td><td>phone</td>";
    echo "</tr>";
    while ($row = mysqli_fetch_array($result)) {
    echo "<form method='post'>";
        echo "<tr>";
        echo "<td><input type='text' name='mname' value=" . $row[0] . "> <input type='hidden' name='id' value=" . $row[1] . "></td>";
        echo "<td>" . $row[2] . "</td>";
        echo "<td>" . $row[3] . "</td>";
        echo "<td>" . $row[4] . "</td>";
        echo "<td>" . $row[5] . "</td>";
        echo "<td><input type='submit' name='single' value='edit'></td>";
        echo "</tr>";
    echo "</form>";
    }
    echo "</table>";

    ?>
}

还在表单中使用隐藏字段并在该字段中保留记录ID，并在查询中使用它，因为它将精确查询并提高性能。另一个有用的事情是你应该在每一行都有一个新的表单标签，比如我在while循环中使用了form标签，使用这个代码只会将一个人的id，name发送到你的编辑页面。在您的情况下，它将提交整个数据。

Answer 3

使用此功能。

//Anything goes here
........
$show="SELECT * FROM persons";
$result=mysqli_query($con,$show);
echo "<form method='post'>";
echo "<table border=1>";
echo "<tr>";
echo "<td>name</td><td>Firstname</td><td>Lastname</td><td>address</td><td>phone</td>";
echo "</tr>";
while ($row=mysqli_fetch_array($result))
{
echo "<tr>";
echo "<td><input type='text' name='mname' value='".$row[0]."'></td>";
echo "<td>".$row[1]."</td>";
echo "<td>".$row[2]."</td>";
echo "<td>".$row[3]."</td>";
echo "<td>".$row[4]."</td>";
echo "<td><input type='submit' name='single' value='edit'></td>";
echo "</tr>";
}
echo "</table>";
echo "</form>";
?>
<?
if (isset($_POST['single']))
{
 $show="SELECT * FROM persons WHERE name='".$_POST[mname]."'";
  //another sql query here
   ............
   .............

PHP：如何使用sql查询结果

3 个答案: