Question

我写了这个查询给了我当天的记录

SELECT EnquiryOwner,Count(uid) 
FROM EnquiryMaster 
WHERE orgid = '" + orgid + "' 
    AND (DAY(date) = DAY(GETDATE()) 
    AND MONTH(date) = MONTH(GETDATE()) 
    AND YEAR(date) = YEAR(GETDATE())) 
GROUP BY EnquiryOwner

我想选择一周的记录。如果我在星期二访问，我想要从上周二到本周二的记录

Answer 1

You can use dateadd to determine the date of one week before.

E.g。像

DAY(date)   = DATEADD(day,   -7, GETDATE()) AND    
MONTH(date) = DATEADD(month, -7, GETDATE()) AND
YEAR(date)  = DATEADD(year,  -7, GETDATE())

或

... WHERE date between DATEADD(DAY,-7,GETDATE()) and GETDATE()

另请参阅date and time functions列表。

Answer 2

如果你不关心时间：

WHERE date between DATE_SUB(DATE(NOW()),INTERVAL 7 DAY) and DATE(NOW())

如果你关心时间：

WHERE date between DATE_SUB(NOW(),INTERVAL 7 DAY) and NOW()

这是MYSQL。对于SQL Server，它看起来像这样：

WHERE date between DATEADD(DAY,-7,GETDATE()) and GETDATE()

（我没有安装sql server，因此未经过测试。）

Answer 3

如果你想跳一周，你只需要使用dateadd比较一个日期减去7。

SELECT EnquiryOwner,Count(uid) 
FROM EnquiryMaster 
WHERE orgid = '" + orgid + "' 
    AND date = DATEADD(date, -7, GETDATE()) 
GROUP BY EnquiryOwner

选择星期记录

3 个答案: