Python 3.3 - 从列表和.txt读取多项选择然后评分

时间:2013-04-16 01:59:40

标签: python list testing

我已经用三种不同的方式尝试过这个程序,我知道我已经接近几次但是在失败多次之后我已经放弃并且需要额外的一组眼睛。 该程序“简单”我知道,但我知道我在想它。

程序应将正确的答案存储在列表中。使用该列表对20个问题测试进行评分。 然后阅读该student.txt文件以确定学生的答案。 读完.txt文件后,它应该分级然后显示通过或失败(传递= 15或更高) 它最终显示总数或正确,错误的答案以及学生错过的问题列表。

以下是所有三次尝试。非常感谢任何帮助。


answerKey = [ B, D, A, A, C, A, B, A, C, D, B, C, D, A, D, C, C, B, D, A,]

studentExam = [ B, D, A, D, C, A, B, A, C, A, B, C, D, A, D, C, C, B, D, A,]

index = 0 

numCorrect = 0

for answerLine, studentLine in zip (answerKey, studentExam):
    answer = answerLine.split()
    studentAnswer = studentLine.split()

    if studentAnswer != answer:
        print( 'You got that question number', index + 1, 'wrong\n the correct,\
        answer was' ,answer, 'but you answered' , studentAnswer)
        index += 1
    else:
        numCorrect += 1
        index += 1

    grade = int((numCorrect / 20) * 100)

    print (' The number of correctly answered questions: ', numCorrect)

    print (' The number of incorrectly answered questions: ', 20 - numCorrect)

    print (' Your grade is', grade, '%')

    if grade <= 75:
        print (' You have not passed ')
    else:
        print (' Congrats you have passed ')

answerKey.close()
studentExam.close()

# This program stores the correct answer for a test
# then reads students answers from .txt file
# after reading determines and dislpays pass or fail (15 correct to pass)
# Displays number of correct and incorrect answers for student
# then displays the number for the missed question/s

#Creat the answer list
def main ( ): 
    # Create the answer key list
    key = [ B, D, A, A, C, A, B, A, C, D, B, C, D, A, D, C, C, B, D, A,]

    print (key)

# Read the contents of the student_answers.txt and insert them into a list
def read_student( ):
    # Open file for reading
    infile = open ( 'student_answers.txt', 'r' )

    # Read the contents of the file into a list
    student = infile.readlines ( )

    # Close file
    infile.close ( )

    # Strip the \n from each element
    index = 0
    while index < len(student):
        student[index] = student[index].rstrip ( '\n' )

    # Print the contents of the list
    print (student)

# Determine pass or fail and display all results 
def pass_fail(answers, student):

    # Lists to be used to compile amount correct, 
    # amount wrong, and questions number missed
    correct_list = []
    wrong_list = []
    missed_list = []

    # For statement to compile lists
    for ai,bi in zip (key,student):
        if ai == bi:
            correct_list.append(ai)
        else:
            wrong_list.append(ai)
            missed_list.append(ai)

    # Printing results for user
    print(correct_list,' were answered correctly')

    print(wrong_list,' questions were missed')

    # If statement to determine pass or fail
    if len(correct_list) >=15:
        print('Congrats you have passed')
    else: 
        print('Sorry you have faild please study and try, \
         again in 90 days')
        print('Any attempt to retake test before 90 days, \
        will result in suspension of any licenses')

    # Displaying the question number for the incorrect answer
    print ( 'You missed questions number ', missed_list)


main()

a = (1, 'A'),(2,'C'),(3,'B')
b = (1,'A'), (2,'A'),(3,'C')

correct_list = []

wrong_list = []

missed_list = []

for ai, bi in zip (a, b):
    if ai == bi:
        correct_list.append(ai)
    else:
        wrong_list.append(ai)
        missed_list.append(ai)
index(ai)+1


print(correct_list,'answered correct')

print(wrong_list, 'answered wrong')

if len(correct_list) >=2:
    print ('Congrats you have passed')
else:
    print ('Sorry you have faild please study and try again in 90 days')
    print('Any attempt to retake test before 90 days will result in suspension of any     lisences')


print ('Question number missed', missed_list)

3 个答案:

答案 0 :(得分:2)

所以,我决定放弃你的第二个例子,因为这对我来说是最容易的。

这是一个修改过的文件,带有解释,可以实现我想要的功能。我假设学生的答案在一个名为student_answers.txt的文本文件中,每行有一个答案。

#!/usr/bin/env python

def read_student(path):
    with open(path, 'r') as infile:
        contents = infile.read()

    # Automatically gets rid of the newlines.
    return contents.split('\n') 

def pass_fail(answers, student):
    correct_list = []
    wrong_list = []

    # Use the 'enumerate' function to return the index.
    for index, (ai, bi) in enumerate(zip(answers, student)):
        # since problems start with 1, not 0
        problem_number = index + 1 

        if ai == bi:
            correct_list.append(problem_number)
        else:
            wrong_list.append(problem_number)

    # Print the length of the list, not the list itself.
    print(len(correct_list), 'were answered correctly')
    print(len(wrong_list), 'questions were missed')

    if len(correct_list) >= 15:
        print('Congrats, you have passed')
    else: 
        print('Sorry, you have failed. Please study and try again in 90 days')
        print('Any attempt to retake test before 90 days will result in suspension of any licenses')

    # Display each missed number on a separate line
    print ('You missed questions numbers:')
    for num in wrong_list:
        print('    ' + str(num))



def main( ): 
    key = ['B', 'D', 'A', 'A', 'C', 'A', 'B', 'A', 'C', 'D', 'B', 'C', 
        'D', 'A', 'D', 'C', 'C', 'B', 'D', 'A']
    student_answers = read_student('student_answers.txt')
    pass_fail(key, student_answers)

if __name__ == '__main__':
    main()

一些一般性意见:

  • main函数中,您创建了一个密钥,将其打印出来,并尝试在pass_fail函数中访问它。这不起作用 - 当您在函数内部创建变量时,它不会在函数外部自动访问。你可以做几个解决方案:
    • 使key成为全局变量。这是undesirable solution
    • key变量传递到pass_fail函数。这就是我所做的。
  • 您阅读学生档案的代码有点过于复杂。您可以使用with语句,它会自动打开和关闭文件对象(infile)。类似地,Python提供了内置的方法来帮助拆分文本文件中的字符串并删除换行符。此外,对于将来,您还可以迭代文件中的每一行,而不是手动循环:

    with open('file.txt') as my_file:
         for line in my_file:
             print(line) 
             # The newline is still a part of the string!
    
  • 我不确定为什么wrong_list内有missed_listpass_fail个变量。我删除了missed_list

  • for循环的问题在于您存储了正确的答案,而不是问题编号。为了解决这个问题,我使用了内置的enumerate函数,这对于这类事情非常有用。或者,您可以使用变量并在每个循环中增加一次。
  • 您的print陈述有点格格不入,所以我清理了
  • 为用户打印结果时,您不想打印列表。而是要打印列表的长度
  • 我不知道这是否是故意的,但你的钥匙上没有字符串,而只是字母名称。

答案 1 :(得分:0)

你的第一个答案是相当接近的,只是Python将A,B,C和D解释为变量而不是字符。你在for循环中留下了评分逻辑。将数组更改为字符而不是变量后,我得到以下结果:

 The number of correctly answered questions:  1
 The number of incorrectly answered questions:  19
 Your grade is 5 %
 You have not passed 
 The number of correctly answered questions:  2
 The number of incorrectly answered questions:  18
 Your grade is 10 %
 You have not passed 
 The number of correctly answered questions:  3
 The number of incorrectly answered questions:  17
 Your grade is 15 %
 You have not passed 
You got that question number 4 wrong
 the correct,        answer was ['A'] but you answered ['D']
 The number of correctly answered questions:  3
 The number of incorrectly answered questions:  17
 Your grade is 15 %
 You have not passed 
 The number of correctly answered questions:  4
 The number of incorrectly answered questions:  16
 Your grade is 20 %
 You have not passed 
 The number of correctly answered questions:  5
 The number of incorrectly answered questions:  15
 Your grade is 25 %
 You have not passed 
 The number of correctly answered questions:  6
 The number of incorrectly answered questions:  14
 Your grade is 30 %
 You have not passed 
 The number of correctly answered questions:  7
 The number of incorrectly answered questions:  13
 Your grade is 35 %
 You have not passed 
 The number of correctly answered questions:  8
 The number of incorrectly answered questions:  12
 Your grade is 40 %
 You have not passed 
You got that question number 10 wrong
 the correct,        answer was ['D'] but you answered ['A']
 The number of correctly answered questions:  8
 The number of incorrectly answered questions:  12
 Your grade is 40 %
 You have not passed 
 The number of correctly answered questions:  9
 The number of incorrectly answered questions:  11
 Your grade is 45 %
 You have not passed 
 The number of correctly answered questions:  10
 The number of incorrectly answered questions:  10
 Your grade is 50 %
 You have not passed 
 The number of correctly answered questions:  11
 The number of incorrectly answered questions:  9
 Your grade is 55 %
 You have not passed 
 The number of correctly answered questions:  12
 The number of incorrectly answered questions:  8
 Your grade is 60 %
 You have not passed 
 The number of correctly answered questions:  13
 The number of incorrectly answered questions:  7
 Your grade is 65 %
 You have not passed 
 The number of correctly answered questions:  14
 The number of incorrectly answered questions:  6
 Your grade is 70 %
 You have not passed 
 The number of correctly answered questions:  15
 The number of incorrectly answered questions:  5
 Your grade is 75 %
 You have not passed 
 The number of correctly answered questions:  16
 The number of incorrectly answered questions:  4
 Your grade is 80 %
 Congrats you have passed 
 The number of correctly answered questions:  17
 The number of incorrectly answered questions:  3
 Your grade is 85 %
 Congrats you have passed 
 The number of correctly answered questions:  18
 The number of incorrectly answered questions:  2
 Your grade is 90 %
 Congrats you have passed 
Traceback (most recent call last):
  File "a1.py", line 39, in <module>
    answerKey.close()
AttributeError: 'list' object has no attribute 'close'

最后一个错误是因为你已经关闭了一个可能是文件对象的数组,但是你非常接近。只是一个小的语法错误。

答案 2 :(得分:0)

简短版本,但是完成了工作。

correct = ['B', 'D', 'A', 'A', 'C', 'A', 'B', 'A', 'C', 'D', 'B', 'C', 'D', 'A', 'D', 'C', 'C', 'B', 'D', 'A']
file_handler = open('student_answers.txt','r')
answers = file_handler.readlines()
valid = 0
for element in enumerate(correct):
    if answers[element[0]].rstrip("\n") == element[1]:
        valid += 1
if valid >= 15:
    print("Congrats, you passed with " + str((valid/20)*100) + "%")
else:
    print("Sorry, you failed with " + str((valid/20)*100) + "%")