Question

我一直在逐行搜索我的代码，试图找到错误，但我还没有成功。

下面显示的是我的输入和更新文件的片段。

modifyform.php

                    <li id="li_1" >
        <label class="description" for="servername">Server Name </label>
        <div>
            <input id="element_1" name="Servername" class="element text medium" type="text" maxlength="255" value="<?php echo $person['servername']; ?>"/> 
        </div><p class="guidelines" id="guide_1"><small>Enter your server name here NOT your server address.</small></p> 
        </li>       <li id="li_2" >
        <label class="description" for="Serveraddress">Server Address </label>
        <div>
            <input id="element_2" name="Serveraddress" class="element text medium" type="text" maxlength="255" value="<?php echo $person['serveraddress']; ?>"/> 
        </div><p class="guidelines" id="guide_2"><small>This will the DNS name of your server</small></p> 
        </li>       <li id="li_3" >
        <label class="description" for="Portnumber">PortNumber </label>
        <div>
            <input id="element_3" name="Portnumber" class="element text medium" type="text" maxlength="255" value="<?php echo $person['portnumber']; ?>"/> 
        </div><p class="guidelines" id="guide_3"><small>This will be the port your server is using.</small></p> 

        <label class="description" for="Status">Server Status </label>
               <div>
            <input id="element_4" name="Status" class="element text medium" type="text" maxlength="255" value="<?php echo $person['status']; ?>"/> 
        </div><p class="guidelines" id="guide_4"><small> Display your Server Status</small></p> 

        </li>       <li id="li_4" >
        <label class="description" for="Description">Server Description </label>
        <div>
            <textarea id="element_5" name="Description" class="element textarea medium" value ="<?php echo $person['description']; ?>"></textarea> 
        </div><p class="guidelines" id="guide_5"><small>Enter server description/rules here.</small></p> 
        </li>

                    <li class="buttons">
                <input type="hidden" name="id" value="<?php echo $_GET['id']; ?>" />

                <input id="saveForm" class="button_text" type="submit" name="submit" value="Modify" />
        </li>
            </ul>
        </form> 
        <div id="footer">
        </div>
    </div>

    </body>-
</html>

modifyame.php

<?php


mysql_connect("localhost", "user", "password") or die (mysql_error());
#echo "Connected to MYSQL ";
mysql_select_db("starforg_search") or die (mysql_error());
#echo "Connected to Data Base";
/*$query = "SELECT * FROM table WHERE userId='{$user_id}'";
$result = mysql_query ($query) or die (mysql_error());*/

    if(!isset($_POST['submit'])) {
    $q = "SELECT * FROM addserverame WHERE ID = $_GET[id] AND userId='{$user_id}'";
    $result = mysql_query ($q);
    $person = mysql_fetch_array ($result);
    }

    ?>



<?

if(isset($_POST['submit'])) {
    $u = "UPDATE addserverame SET `servername`='$_POST[Servername]', `serveraddress`='$_POST[Serveraddress]', `portnumber`='$_POST[Portnumber]', `status`='$_POST[Status]', `description`='$_POST[Description]', WHERE ID = $_POST[id] AND userId='{$user_id}'";
    mysql_query($u) or die (mysql_error());
    echo "Server Info Has Been Modified";
}
?>

问题区域 更新和回显servername，serveraddress和portnumber字段很好，但回显/更新描述和状态字段不起作用。

我已多次查看表名，我承认它们是正确的。

这让我相信语法错误可能是罪魁祸首。

感谢您的时间

本

Answer 1

UPDATE声明中存在语法错误。在,子句之前，您应该删除额外的WHERE。

UPDATE  addserverame 
SET  `servername`='$_POST[Servername]', 
     `serveraddress`='$_POST[Serveraddress]', 
     `portnumber`='$_POST[Portnumber]', 
     `status`='$_POST[Status]', 
     `description`='$_POST[Description]', -- <<=== REMOVE extra comma HERE
WHERE ID = $_POST[id] AND 
      userId='{$user_id}'

养成对齐代码的习惯，以便轻松发现语法错误。

作为旁注，如果变量的值（ s ）来自外部，则查询易受SQL Injection攻击。请查看下面的文章，了解如何防止它。通过使用PreparedStatements，您可以摆脱在值周围使用单引号。

How to prevent SQL injection in PHP?

你能找到逻辑/语法错误

1 个答案: