Question

在PHP方面经验丰富，但对jQuery不熟悉：我想用ajax从json编码的php文件中获取数据来填充一个简单的数据表。

table.php：HTML代码段

<head>...
<script type="text/javascript" charset="utf-8">
    $(document).ready(function() {
        $('#example').dataTable({
            "bProcessing": true,
            "sAjaxSource": 'deliver_tests.php',
            "sScrollY": "200px",
        "bPaginate": false
        });
    } );
</script>
</head>    
<body> ...
<div id="demo">
    <table cellpadding="0" cellspacing="0" border="0" class="display" id="example" width="100%">
    <thead>
        <tr>
        <th>id</th>
        <th>Status</th>
        <th>Abkürzung</th>
        <th>Test</th>
        <th>Patient</th>
        <th>Datum</th>
    </tr>
    </thead>
    <tbody></tbody>
    </table>
</div>

deliver_tests.php：代码段

try {
    $sql = "SELECT tsID, tsStatus, tbShortname, tbName, paCode, tsCompleted_Date FROM test LEFT JOIN testbase ON tsTestBaseID = tbID LEFT JOIN patient ON tsPatientID = paID WHERE tsAccountID=:accID ORDER BY tsCompleted_Date DESC";
    $dbTests = $objDB->prepare($sql);
    $bind=array('accID' => $_SESSION['aID']);
    $dbTests->execute($bind);
    $tests = $dbTests->fetchAll(PDO::FETCH_ASSOC);
} catch (PDOException $dbe) {
    // error 
}
$tests = array('aaData' => $tests);
echo json_encode($tests);

在此处查看其输出：http://pastebin.com/uZiLepSb

致电table.php，我收到 js-alert：

DataTables warning (table id = 'example'): 
Requested unknown parameter '0' from the data source for row 0

我想我必须重新组合那个数组？我需要提示如何从这里继续 - 谢谢你提前！

Answer 1

每个表行都需要是一个数组而不是JSON中的对象，您应该可以使用PDO::FETCH_NUM代替PDO::FETCH_ASSOC来执行此操作。

请参阅：DataTables AJAX source example

PHP：提供JSON以填充数据表

1 个答案: