解析名称没有空格?

时间:2013-04-15 21:44:24

标签: java

当用户输入多个空格时,我的程序无法正确打印用户的名称。例如,如果用户输入他们的名字后跟2个空格然后输入他们的姓氏,我的程序会假设这些额外的空格是中间名,并将中间名作为空格打印,将姓氏打印为输入的第二个字符串,即使只输入了两个字符串。如何改善此问题,以便用户可以输入的额外空间不算作中间名或姓?

public static void main(String[] args)
{
    Scanner sc = new Scanner(System.in);

    System.out.println("Welcome to the name parser.\n");
    System.out.print("Enter a name: ");
    String name = sc.nextLine();

    name = name.trim();

    int startSpace = name.indexOf(" ");
    int endSpace = name.indexOflast(" ");
    String firstName = "";
    String middleName = "";
    String lastName = "";

    if(startSpace >= 0)
    {
        firstName = name.substring(0, startSpace);
        if(endSpace > startSpace)
        {
            middleName = name.substring(startSpace + 1, endSpace);
        }
        lastName = name.substring(endSpace + 1, name.length());
    }
    System.out.println("First Name: " + firstName);
    System.out.println("Middle Name: " + middleName);
    System.out.println("Last Name: " + lastName);
}

输出:joe mark

First name: joe
Middle name: // This shouldn't print but because the user enter extra spaces after first name the spaces becomes the middle name.
Last name: mark 

1 个答案:

答案 0 :(得分:3)

试试这个

 // replaceAll needs regex so "\\s+" (for whitespaces)
 // s+ look for one or more whitespaces
 // replaceAll will replace those whitespaces with single whitespace.
 // trim will remove leading and trailing whitespaces

 name = name.trim().replaceAll("\\s+", " ");

1. Java Regex

2. replaceAll API